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devlian [24]
3 years ago
11

What is the value of x?

Mathematics
1 answer:
Drupady [299]3 years ago
3 0
I think we have to use Pythagorean Therom here
a² + b² = c²
First we need to know the height of the Triangle (which is YT)
Let "b" be the height YT:
22² + b² = 77²
484 + b² = 5929
b² = 5929 - 484 = 5445
√b² = √(5445)
b = √5445 = 73.79ft
 Now that we have the height lets find the missing base(YK):
We are going to use the same formula, but this time to find the base and with a different triangle.
a² + 73.79² = 87.5²
a² + 5444.96 = 7656.25
a² = 7656.25 - 5444.96
a² = 2211.29
√a² = √(2211.29)
a = √2211.29 = 47.02
Now we can add the bases together to find x.
Bases "VY" and "YK"
x = 22+47
x = 69
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2 years ago
What is the value of x 4x-1+2x-9=152
Aleonysh [2.5K]

Rearrange:


Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :


                    4*x-1+2*x-9-(152)=0

Step by step solution :

Step  1  :

Pulling out like terms :


1.1     Pull out like factors :


  6x - 162  =   6 • (x - 27)

step 2

Solving a Single Variable Equation :


2.2      Solve  :    x-27 = 0


Add  27  to both sides of the equation :

                     x = 27

One solution was found :

                  x = 27




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5 0
3 years ago
A particular concentration of a chemical found in polluted water has been found to be lethal to 20% of the fish that are exposed
torisob [31]

Answer:

a) P(X=14)=(20C14)(0.8)^{14} (1-0.8)^{20-14}=0.109

b) P(X\geq 10) = 1-P(X \leq 9) = 0.9994

c) P(X \leq 16)= 1-P(X>16) =1-P(X \geq 17)= 1- [P(X=17) +...+P(X=20)]=0.589

d) E(X)= np = 20 *0.8 = 16

Var(X) = np(1-p) = 20*0.8*(1-0.8) = 3.2

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=20, p=1-0.2=0.8)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

Part a

For this case we want this probability:

P(X=14)

And using the mass function we have this:

P(X=14)=(20C14)(0.8)^{14} (1-0.8)^{20-14}=0.109

Part b

For this case we want this probability:

P(X \geq 10)

And we can find this using the complement rule:

P(X\geq 10) = 1-P(X

P(X=0)=(20C0)(0.8)^{0} (1-0.8)^{20-0}=1.05x10^{-14}

P(X=1)=(20C1)(0.8)^{1} (1-0.8)^{20-1}=8.39x10^{-13}

P(X=2)=(20C2)(0.8)^{2} (1-0.8)^{20-2}=3.19x10^{-11}

P(X=3)=(20C3)(0.8)^{3} (1-0.8)^{20-3}=7.65x10^{-10}

P(X=4)=(20C4)(0.8)^{4} (1-0.8)^{20-4}=1.30x10^{-8}

P(X=5)=(20C5)(0.8)^{5} (1-0.8)^{20-5}=1.66x10^{-7}

P(X=6)=(20C6)(0.8)^{6} (1-0.8)^{20-6}=1.66x10^{-6}

P(X=7)=(20C7)(0.8)^{7} (1-0.8)^{20-7}=1.33x10^{-5}

P(X=8)=(20C8)(0.8)^{8} (1-0.8)^{20-8}=8.65x10^{-5}

P(X=9)=(20C9)(0.8)^{9} (1-0.8)^{20-9}=0.00046

And if we replace we got:

P(X\geq 10) = 1-P(X \leq 9) = 0.9994

Part c

For this case we want this probability:

P(X \leq 16)

And we can use the complement rule like this:

P(X \leq 16)= 1-P(X>16) =1-P(X \geq 17)= 1- [P(X=17) +...+P(X=20)]

P(X=17)=(20C17)(0.8)^{17} (1-0.8)^{20-17}=0.205

P(X=18)=(20C18)(0.8)^{18} (1-0.8)^{20-18}=0.137

P(X=19)=(20C19)(0.8)^{19} (1-0.8)^{20-19}=0.0576

P(X=20)=(20C20)(0.8)^{20} (1-0.8)^{20-20}=0.0115

And if we replace we got:

P(X \leq 16)= 1-P(X>16) =1-P(X \geq 17)= 1- [P(X=17) +...+P(X=20)]=0.589

Part d

The expected value is given by:

E(X)= np = 20 *0.8 = 16

Var(X) = np(1-p) = 20*0.8*(1-0.8) = 3.2

3 0
3 years ago
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