Triangular sail has a baseline of 2.5 m. The area of the sail 3.75 m². How tall is the sail?

Mathematics

1 answer:

Debora [2.8K]4 years ago

3 0

Check the picture below.

You might be interested in

What is h(x)=7+10x+x^2 written in vertex form?

Morgarella [4.7K]

Answer:

h(x) = (x + 5)² - 18

Step-by-step explanation:

Given

h(x) = 7 + 10x + x² = x² + 10x + 7

To obtain vertex form, use the method of completing the square

add/ subtract ( half the coefficient of the x- term )² to x² + 10x

h(x) = x² + 2(5)x + 25 - 25 + 7

= (x + 5)² - 18 ← in vertex form

6 0

4 years ago

PLease NEED HELP! thank you

adelina 88 [10]

.32 is the answer to this question

7 0

3 years ago

Solve sin^4(x)+cos^4(x)=cos4x

ICE Princess25 [194]

$\sin^4x=(\sin^2x)^2=\left(\dfrac{1-\cos2x}2\right)^2=\dfrac{1-2\cos2x+\cos^22x}4$
$\cos^4x=(\cos^2x)^2=\left(\dfrac{1+\cos2x}2\right)^2=\dfrac{1+2\cos2x+\cos^22x}4$

$\implies \sin^4x+\cos^4x=\dfrac{2+2\cos^22x}4=\dfrac{1+\cos^22x}2$

$\cos^22x=\dfrac{1+\cos4x}2$
$\implies\sin^4x+\cos^4x=\dfrac{1+\frac{1+\cos4x}2}2=\dfrac{3+\cos4x}4$

So the equation reduces to

$\dfrac{3+\cos4x}4=\cos4x$
$\dfrac34=\dfrac34\cos4x$
$\cos4x=1$

We have $\cos\theta=1$ whenever $\theta=0+2k\pi=2k\pi$ , where $k$ is any integer. This means for this equation we have solutions at

$4x=2k\pi\implies x=\dfrac{k\pi}2$