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2 years ago

Anna is making a banner out of 4 congruent triangles as shown below. How much blue trim will she need for each side

Mathematics

1 answer:

Ede4ka [16]2 years ago

3 0

Answer:

The length of each blue trim is 17.2 inches

Step-by-step explanation:

Given

See attachment for banner

Required

The length of each blue trim

Since all 4 triangles are equal, then the dimension of 1 triangle is:

$Side\ 1 = 10$

$Side\ 2 = 14$

The hypotenuse (x) of the triangle blue trim is represented by the blue trim

So:

$x^2 = Side\ 1^2 + Side\ 2^2$

This gives

$x^2 = 10^2 + 14^2$

$x^2 = 100 + 196$

$x^2 = 296$

Take square root

$x = \sqrt{296$

$x = 17.2in$

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HELP PLEASE LOTS OF POINTS

inna [77]

We are given

p: 1 is the multiplicative identity

Firstly, we will verify whether it is true

Multiplicative identity:

$A \cdot 1=A$

Here , 1 is the multiplicative identity

So, 1 is multiplicative identity

so, statement p is true

q: a · 0 = a

we know that whenever we multiply any expression by 0

It will result in 0

so, this statement is false

now, we will verify each options

option-A:

p \/ q

so, we can plug

T \/ F = T

so, this is TRUE

option-B:

p /\ q

so, we can plug

T /\ F = F

so, this is FALSE

option-C:

p --> q

we can plug

T-->F = F

so, this is FALSE

8 0

3 years ago

A field researcher is gathering data on the trunk diameters of mature pine and spruce trees in a certain area. The following are

lidiya [134]

Answer:

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

Step-by-step explanation:

Using a .10 significance level, can he conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree

The null hypothesis is that they are equal(that is, subtraction between the means is 0), while the alternate hypothesis is that they are greater(that is, subtraction between the means is larger than 0). So

$H_0: \mu_1 - \mu_2 = 0$

$H_a: \mu_1 - \mu_2 > 0$

In which $\mu_1$ is the mean pine trees height while $\mu_2$ is the mean spruce trees height.

The test statistic is:

$z = \frac{X - \mu}{s}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis and s is the standard error.

0 is tested at the null hypothesis:

This means that $\mu = 0$

Mean trunk diameter (cm) 35 30:

Pine trees - 35

Spruce trees - 30

The sample mean is given by the subtraction of the means. So

$X = 35 - 30 = 5$

Sample Size 40 80

Population variance 160 160

This means that the standard error for each sample is given by:

$s_1 = \frac{\sqrt{160}}{\sqrt{40}} = 2$

$s_1 = \frac{\sqrt{160}}{\sqrt{80}} = \sqrt{2}$

The standard error of the difference is the square root of the sum squared of the standard error of each sample.

$s = \sqrt{2^2 + (\sqrt{2})^2} = \sqrt{6} = 2.4495$

Test statistic:

$z = \frac{X - \mu}{s}$

$z = \frac{5 - 0}{2.4495}$

$z = 2.04$

Pvalue of the test:

Probability of a sample mean larger than 5, which is 1 subtracted by the pvalue of Z when X = 5.

Looking at the z-table, z = 2.04 has a pvalue of 0.9793.

1 - 0.9793 = 0.0207

As the pvalue of the test is 0.02097 < 0.1, using a .10 significance level, he can conclude that the average trunk diameter of a pine tree is greater than the average diameter of a spruce tree.

8 0

2 years ago

10 to 15 simplified

pashok25 [27]

2/3
Divide the numerator and denominator by their gcd which is 5

4 0

2 years ago

Read 2 more answers

What is the Y interpret of the question? y=-1/2x-6

Oduvanchick [21]

Answer:

The y-intercept is (0,-6)