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2 years ago

I need help on this.

Mathematics

1 answer:

andrew11 [14]2 years ago

3 0

To find the midpoint, add x1 and x2 then divide by 2, then add y1 and y2 and divide by 2.

Midpoint = (2a +2b /2 , 0 + 2c /2)

Midpoint = a+b, c

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2 years ago

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Step-by-step explanation

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3 years ago

2x^2=9-3x <br> Find the factors

d1i1m1o1n [39]

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x = -3, $\frac{3}{2}$

Step-by-step explanation:

The given quadratic equation is: $2x^2 = 9 - 3x$

This can be written as: $2x^2 + 3x - 9 = 0$

To solve a quadratic equation of the form $ax^2 + bx + c = 0$ we use the formula:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

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Therefore, the roots of the equation are:

$x = \frac{- 3 \pm \sqrt{9 - 4(2)(-9)}}{2(2)}$

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We get two values of 'x', viz.,

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Since the factors of the quadratic equation is asked, we write it as:

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because, if (x - a)(x - b) are the factors of a quadratic equation, then 'a' and 'b' are its roots.

Multiply (x + 3) and (x - $\frac{3}{2}$ to see that this indeed is the given quadratic equation.

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3 years ago