Combine like terms
-x = 4 + 6 - 3x
-x = 10 - 3x
Isolate the x, add 3x to both sides
-x (+3x) = 10 - 3x (+3x)
-x + 3x = 10
Simplify. Combine like terms
-x + 3x = 10
2x = 10
Isolate the x, divide 2 from both sides
2x/2 = 10/2
x = 10/2
x = 5
x = 5, or A is your answer
hope this helps
Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60

t=1
Answer:
To be honest i dont even know
Step-by-step explanation:
ummmm