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laila [671]
3 years ago
9

X^2-8x-36=0 how to solve this quadratic equation?

Mathematics
1 answer:
My name is Ann [436]3 years ago
7 0
I hope this helps you

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2/3 * 2/3 divid (2/5 divide 3/5) answer plz
hichkok12 [17]

Answer for Q.1 = 4/9     
Answer for Q2. = 2/3
6 0
3 years ago
Use the substitution method to solve.<br><br> y=5−3x<br> 5x−4y=−3
Vadim26 [7]
Well just substitute y (the first equation) into the second equation.
So
5x-4(5-3x)=-3
Then just solve the equation from there.
5x-20+12x=-3
17x=17
x=1
and if you need y, y=2
6 0
3 years ago
What is 5/10 + 2/10 ?
Daniel [21]

Step-by-step explanation:

5/10+2/10

7/10

0.7

................

4 0
3 years ago
HELP NEEDED ASAP <br> answer this question for me, image below
maks197457 [2]

Answer: Heyaa! ~

Your Answer Is... 13

Step-by-step explanation:

  • 385 divided by 28 = 13. 75
  • Reduce the expression, if possible, by cancelling the common factors.

Hopefully this helps you! ~

6 0
2 years ago
Evaluate each finite series for the specified number of terms. 1+2+4+...;n=5
zaharov [31]

Answer:

31

Step-by-step explanation:

The series are given as geometric series because these terms have common ratio and not common difference.

Our common ratio is 2 because:

1*2 = 2

2*2 = 4

The summation formula for geometric series (r ≠ 1) is:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}} or \displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

You may use either one of these formulas but I’ll use the first formula.

We are also given that n = 5, meaning we are adding up 5 terms in the series, substitute n = 5 in along with r = 2 and first term = 1.

\displaystyle \large{S_5=\frac{1(2^5-1)}{2-1}}\\\displaystyle \large{S_5=\frac{2^5-1}{1}}\\\displaystyle \large{S_5=2^5-1}\\\displaystyle \large{S_5=32-1}\\\displaystyle \large{S_5=31}

Therefore, the solution is 31.

__________________________________________________________

Summary

If the sequence has common ratio then the sequence or series is classified as geometric sequence/series.

Common Ratio can be found by either multiplying terms with common ratio to get the exact next sequence which can be expressed as \displaystyle \large{a_{n-1} \cdot r = a_n} meaning “previous term times ratio = next term” or you can also get the next term to divide with previous term which can be expressed as:

\displaystyle \large{r=\frac{a_{n+1}}{a_n}}

Once knowing which sequence or series is it, apply an appropriate formula for the series. For geometric series, apply the following three formulas:

\displaystyle \large{S_n=\frac{a_1(r^n-1)}{r-1}}\\\displaystyle \large{S_n=\frac{a_1(1-r^n)}{1-r}}

Above should be applied for series that have common ratio not equal to 1.

\displaystyle \large{S_n=a_1 \cdot n}

Above should be applied for series that have common ratio exactly equal to 1.

__________________________________________________________

Topics

Sequence & Series — Geometric Series

__________________________________________________________

Others

Let me know if you have any doubts about my answer, explanation or this question through comment!

__________________________________________________________

7 0
3 years ago
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