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just olya [345]
3 years ago
15

A rectangular swimming pool that is 10 ft wide by 16 ft long is surrounded by a cement sidewalk of uniform width. If the area of

the sidewalk is 155 ft2, what is its width?

Mathematics
1 answer:
Alchen [17]3 years ago
5 0
We are asked to solve for the width "x" in the given problem. To visualize the problem, see attached drawing.
We have the area of the swimming pool such as:
Area SP = l x w
Area SP = 10 * 16
Area SP = 160 feet2
Area of the swimming pool plus the sidewalk with uniform width:
Area SP + SW = (10 + x) * (16 + x)
160 + 155 = 160 + 10x + 16x + x2
160 -160 + 155 = 26x + x2
155 = 26 x + x2
x2 + 26x -155= 0
Solving for x, we need to use quadratic formula and the answer is 5 feet.

The value of x is <span>5 feet. </span>

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a. The next four terms are 5/10, -6/11, 7/12, -8/13.

b. The explicit equation for f (n) is f(n) = (-1)ⁿ × (n+1)/(n+6) , n = 0,1,2,3...

c. If n = 53, then (-1)ⁿ = (-1)⁵³ = -1. so, f(n) is negative.

What is the explicit equation?

Without expressing the other terms of the sequence, explicit formulas are always utilized to represent any term of the sequence. The word "explicit" means something that may be found directly without having to know the other phrases in the sequence. A single formula, known as the explicit formula, can be used to describe each term in a series in an individual way.

Explicit formulas of different sequences:

Arithmetic Sequence: aₙ = a + (n - 1) d,

Geometric Sequence: aₙ = a× r^(n - 1),

Harmonic Sequence: aₙ = 1 / [a + (n - 1) d].

Here. we have

Given sequence 1/6, -2/7, 3/8, -4/9

a. The next four terms are 5/10, -6/11, 7/12, -8/13.

b. The explicit equation for f (n) is f(n) = (-1)ⁿ × (n+1)/(n+6) , n = 0,1,2,3...

c. If n = 53, then (-1)ⁿ = (-1)⁵³ = -1. so, f(n) is negative.

To learn more about explicit equations from the given link

brainly.com/question/741967

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Step-by-step explanation:

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Step-by-step explanation:

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Let first consider the equations one by one and will be solving one by one ;

{:\implies \quad \sf x+\dfrac{1}{y}=4}

Multiplying both sides by y will lead ;

{:\implies \quad \sf xy+1=4y}

{:\implies \quad \boxed{\sf xy=4y-1\quad \cdots \cdots(i)}}

Now, consider the second equation which is ;

{:\implies \quad \sf y+\dfrac{1}{x}=\dfrac14}

Multiplying both sides by x will yield

{:\implies \quad \sf xy+1=\dfrac{x}{4}}

{:\implies \quad \sf xy=\dfrac{x}{4}-1}

{:\implies \quad \boxed{\sf xy=\dfrac{x-4}{4}\quad \cdots \cdots(ii)}}

As LHS of both equations (i) and (ii) are same, so equating both will yield;

{:\implies \quad \sf 4y-1=\dfrac{x-4}{4}}

Multiplying both sides by 4 will yield

{:\implies \quad \sf 16y-4=x-4}

{:\implies \quad \sf 16y=x}

Dividing both sides by y will yield :

{:\implies \quad \boxed{\bf{\dfrac{x}{y}=16}}}

<em>Hence, the required answer is 16</em>

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