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monitta
3 years ago
6

Identify a sequence of transformation that maps triangle ABC onto triangle A"B"C" in the image below.

Mathematics
2 answers:
Vladimir79 [104]3 years ago
5 0
I'd go with: D. clockwise 90 rotation; reduction 

(Hope I helped :D
tia_tia [17]3 years ago
5 0

Answer:

C counterclockwise 90 rotation; enlargement

Step-by-step explanation:

From the photo, we can see that triangle A"B"C" is the product of triangle ABC  after the transformation.

Please have a look at point C on line y-axis and after that it lies on x-axis. So we have possible reasons:

1. rotated either counterclockwise 90°

2. rotated clockwise 270°.

The rule is: (x,y)\rightarrow (-y,x)

The corresponding sides of image A"B"C" are bigger than the preimage ABC.  

k=\frac{A"B"}{AB}=\frac{6}{2}=3 > 0

Because k >0, the transformation shows the enlargement

So we choose option C counterclockwise 90 rotation; enlargement

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3 years ago
1.Anthony has decided to purchase a $19,000 car. He plans to put 20% down toward the purchase and to finance the rest at a 6.8%
Nikitich [7]
<h2>First step/Equation</h2>

Answer:

 $362.57

Step-by-step explanation:

A suitable calculator or finance app can find the monthly payment for you. This result comes from a TI-84 calculator.

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The second attachment shows the parameters of the payment function. With 20% down, Anthony is only financing 80% of the price of his car. Of course, there are 12 months in a year, so 4 years worth of payments will be 48 payments. The calculator uses negative values for amounts you pay.

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No doubt your reference material shows you a formula for computing loan payments. One such is ...

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3 0
2 years ago
2 divided by one over 3 the awnser is a fraction
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Jamel watched his older brother Robert lift weights. The bar alone had a mass of 20 kg. On the bar he had tow 11.4 kg weights, t
slavikrds [6]
All you do is add them all together...
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6 0
3 years ago
What would y=x^2 +x+ 2 be in vertex form
balu736 [363]

Answer:

y = (x +  \frac{1}{2} )^{2}  +  \frac{7}{4}

Step-by-step explanation:

y =  {x}^{2}  + x + 2

We can covert the standard form into the vertex form by either using the formula, completing the square or with calculus.

y = a(x - h)^{2}  + k

The following equation above is the vertex form of Quadratic Function.

<u>Vertex</u><u> </u><u>—</u><u> </u><u>Formula</u>

h =  -  \frac{b}{2a}  \\ k =  \frac{4ac -  {b}^{2} }{4a}

We substitute the value of these terms from the standard form.

y = a {x}^{2}  + bx + c

h =  -  \frac{1}{2(1)}  \\ h =  -  \frac{ 1}{2}

Our h is - 1/2

k =  \frac{4(1)(2) - ( {1})^{2} }{4(1)}  \\ k =  \frac{8 - 1}{4}  \\ k =  \frac{7}{4}

Our k is 7/4.

<u>Vertex</u><u> </u><u>—</u><u> </u><u>Calculus</u>

We can use differential or derivative to find the vertex as well.

f(x) = a {x}^{n}

Therefore our derivative of f(x) —

f'(x) = n \times a {x}^{n - 1}

From the standard form of the given equation.

y =  {x}^{2}  +  x + 2

Differentiate the following equation. We can use the dy/dx symbol instead of f'(x) or y'

f'(x) = (2 \times 1 {x}^{2 - 1} ) + (1 \times  {x}^{1 - 1} ) + 0

Any constants that are differentiated will automatically become 0.

f'(x) = 2 {x}+ 1

Then we substitute f'(x) = 0

0 =2x + 1 \\ 2x + 1 = 0 \\ 2x =  - 1 \\x =  -  \frac{1}{2}

Because x = h. Therefore, h = - 1/2

Then substitute x = -1/2 in the function (not differentiated function)

y =  {x}^{2}  + x + 2

y = ( -  \frac{1}{2} )^{2}  + ( -  \frac{1}{2} ) + 2 \\ y =  \frac{1}{4}  -  \frac{1}{2}  + 2 \\ y =  \frac{1}{4}  -  \frac{2}{4}  +  \frac{8}{4}  \\ y =  \frac{7}{4}

Because y = k. Our k is 7/4.

From the vertex form, our vertex is at (h,k)

Therefore, substitute h = -1/2 and k = 7/4 in the equation.

y = a {(x - h)}^{2}  + k \\ y = (x - ( -  \frac{1}{2} ))^{2}  +  \frac{7}{4}  \\ y = (x +  \frac{1}{2} )^{2}  +  \frac{7}{4}

7 0
3 years ago
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