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Elena L [17]
3 years ago
8

I need help on this geometry problem

Mathematics
1 answer:
crimeas [40]3 years ago
6 0

Answer:

ST = 23

RU = 8

SV = 5

SU = 10


Step-by-step explanation:

UV = SV = 5

ST = UT = 23

RU = RS = 8

SU = SV + UV = 5 + 5 = 10


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If h(x)=(fog)(x) and h(x) = sqrt x+5, find g(x) if f(x) = sqrtx+2
Katen [24]

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Step-by-step explanation:

Since we have given that

h(x)=f\circ g(x)

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We need to find the value of g(x):

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3 0
3 years ago
(8y²)(-3x²y²)(2/3xy⁴)<br><br> HELP PLEASEEEEEEEE
IRINA_888 [86]

Step-by-step explanation:

1 Remove parentheses.

8{y}^{2}\times -3{x}^{2}{y}^{2}\times \frac{2}{3}x{y}^{4}

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2

×

3

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2 Use this rule: \frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}

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\frac{8{y}^{2}\times -3{x}^{2}{y}^{2}\times 2x{y}^{4}}{3}

3

8y

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3 Take out the constants.

\frac{(8\times -3\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(8×−3×2)y

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y

2

y

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x

2

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\frac{(-24\times 2){y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

3

(−24×2)y

2

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2

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x

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\frac{-48{y}^{2}{y}^{2}{y}^{4}{x}^{2}x}{3}

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2

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2

y

4

x

2

x

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x

b

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\frac{-48{y}^{2+2+4}{x}^{2+1}}{3}

3

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\frac{-48{y}^{4+4}{x}^{2+1}}{3}

3

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x

2+1

8 Simplify 4+44+4 to 88.

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3

−48y

8

x

2+1

9 Simplify 2+12+1 to 33.

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3

−48y

8

x

3

10 Move the negative sign to the left.

-\frac{48{y}^{8}{x}^{3}}{3}

−

3

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8

x

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-16{y}^{8}{x}^{3}

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2 years ago
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Answer:

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