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Mnenie [13.5K]
3 years ago
5

The low temperatures for a week in winter were -2° F, -15° F, -7° F, 1° F, -4° F, 5° F, 8° F. What was the average low

Mathematics
1 answer:
Novay_Z [31]3 years ago
3 0

Answer: -2 F

Step-by-step explanation:

To find the average, or <em>mean, </em>of a data set, you must first combine all of the values in the set. Since some of these values are negative, it seems more difficult to solve. But it isn't. To find the mean of any data sets, you can find the absolute value of each numerical value. If you combine these regularly, it would be -15, but that is incorrect. The answer is -2 because some of the values may be negative, but you can find the answer easily. Just remember: To find the mean of data sets with negative values, you can find their absolute values, and solve from there. If this does not work for you, then find another solution. But the correct answer is -2 F.

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The opposite sides of a parallelogram have measures (2x+10) cin and (x+15)
xz_007 [3.2K]

Answer:

The measure of the sides is 20 cm.

Step-by-step explanation:

Opposite side of a parallelogram:

Opposite sides of a parallelogram are congruent, that is, they have the same measure.

Measures (2x+10) cm and (x+15) cm:

This means that:

2x + 10 = x + 15

2x - x = 15 - 10

x = 5

2x + 10 = 2*5 + 10 = 10 + 10 = 20

The measure of the sides is 20 cm.

6 0
3 years ago
The answers please. Don’t know how to do #1
daser333 [38]
Your correct. It is what you put down
3 0
3 years ago
Quadrilateral ABCD has coordinates A (3,1) B (4,4) C (7,5) D (6,2). Quadrilateral ABCD is a ?
ASHA 777 [7]
The Quadrilateral ABCD with coordinates (3, 1), (4, 4), (7, 5), (6, 2) is a rhombus because its length and width are both square root of 10 units and adjacent sides are not perpendicular. This can be seen by plotting the points you can either plot it or by using programs.

I hope this helps, God bless, and have a great day!
Brainliest is always appreciated :)
3 0
3 years ago
Read 2 more answers
A solid lies between planes perpendicular to the​ x-axis at x = -2 and x = 2. The​ cross-sections perpendicular to the​ x-axis b
icang [17]

Answer:

V = 128π/3 vu

Step-by-step explanation:

we have that: f(x)₁ = √(4 - x²);  f(x)₂ = -√(4 - x²)

knowing that the volume of a solid is  V=πR²h, where R² (f(x)₁-f(x)₂) and h=dx, then

dV=π(√(4 - x²)+√(4 - x²))²dx;  =π(2√(4 - x²))²dx ⇒

dV= 4π(4-x²)dx , Integrating in both sides

∫dv=4π∫(4-x²)dx , we take ∫(4-x²)dx and we solve

4∫dx-∫x²dx = 4x-(x³/3) evaluated -2≤x≤2 or too 2 (0≤x≤2) , also

∫dv=8π∫(4-x²)dx evaluated 0≤x≤2

V=8π(4x-(x³/3)) = 8π(4.2-(2³/3)) = 8π(8-(8/3)) =(8π/3)(24-8) ⇒

V = 128π/3 vu

8 0
3 years ago
JoAnn works in a publicity office at the state university. She is paid
sleet_krkn [62]
JoAnn works 43 hrs week.
3 0
3 years ago
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