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cupoosta [38]
3 years ago
5

Why is this answer right? Please explain.

Mathematics
1 answer:
Nadya [2.5K]3 years ago
6 0

Answer:

because you divide them by two


Step-by-step explanation:


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Tom earns ​$12 a week mowing lawns. He spends
Gnoma [55]

Answer:

6 dollars on lunch because 36 divided by 6 is 6 lol and you should multiply 1/3 to 2/6 to have an even number so it would be 12 on music and 6 on lunch so 18 total spent and 18 saved

18 total saved

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
How many kilometres on the ground is represented by 9 cm on the map?
Aloiza [94]

Answer:

22500

Step-by-step explanation:

You have to multiply 9 by 25000.

3 0
3 years ago
What is the balance after 7 years if you deposit $2800 in an account that pays 4% interest compounded yearly ?
SVEN [57.7K]

Answer:the balance after 7 years is $3216

Step-by-step explanation:

A) Initial amount deposited into the account is $2800 This means that the principal,

P = 2800

It was compounded yearly. This means that it was compounded once in a year. So

n = 1

The rate at which the principal was compounded is 4%. So

r = 4/100 = 0.04

It was compounded for 7 years. So

t = 7

The formula for compound interest is

A = P(1+r/n)^nt

A = total amount in the account at the end of t years. Therefore

A = 2800(1 + 0.04/2)^ 1× 7

A = 2800(1 + 0.02)^7

A = 2800(1.02)^7

A = $3216

6 0
3 years ago
ASAP Help now 10 pts
Ede4ka [16]

Answer:

$6

Step-by-step explanation:

Each foot cost $2

Hope this helped!

7 0
2 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
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