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3 years ago

14

Type the correct answer in each box. Round your answers to the nearest integer.

2 answers:

QveST [7]3 years ago

5 0

Did you ever find the awnser

Over [174]3 years ago

3 0

Answer:

(1) 92.92 unit (2) 500 unit²

Step-by-step explanation:

(1) Perimeter of the given hexagon ABCDEF will be

= Sum of length of all sides

= AB + BC + CD + DE + EF + FA

= $10+(\sqrt{10^{2}+10^{2}})+\sqrt{10^{2}+10^{2}}+10+\sqrt{20^{2}+10^{2}}+\sqrt{20^{2} +10^{2} }$

= $20+10\sqrt{2} +10\sqrt{2}+10+10\sqrt{(2+1)}+10\sqrt{(2+1)}$

= $(30+20\sqrt{2}+20\sqrt{3})$

= 30 + 28.28 + 34.64

= 92.92 unit

(2) Area of hexagon = Area of ΔAEF + Area of rectangle ABDE + Area of ΔBCD

= $\frac{1}{2} (20)(20)+(20)(10)+\frac{1}{2}(20)(10)$

= 200 + 200 + 100

= 500 unit²

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2 years ago

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3 years ago

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vfiekz [6]

Answer:

Step-by-step explanation:

given a point $(x_0,y_0)$ the equation of a line with slope m that passes through the given point is

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Recall that a line of the form $y=mx+b$ , the y intercept is b and the x intercept is $\frac{-b}{m}$ .

So, in our case, the y intercept is $(y_0-mx_0)$ and the x intercept is $\frac{mx_0-y_0}{m}$ .

In our case, we know that the line is tangent to the graph of 1/x. So consider a point over the graph $(x_0,\frac{1}{x_0})$ . Which means that $y_0=\frac{1}{x_0}$

The slope of the tangent line is given by the derivative of the function evaluated at $x_0$ . Using the properties of derivatives, we get

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Replacing the values in our previous findings we get that the y intercept is

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So regardless of the point we take on the graph, the area of the triangle is always 2.

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3 years ago