Answer:
I have made it in above picture
Answer:
2 / 13
Step-by-step explanation:
Number of cards in a standard deck = 52
Number of 4's = 4 ( 1 for each suit)
Number of 6's = 4 (1 for each suit)
Probability, P = required outcome / Total possible outcomes
P(a 4) = 4 / 52 = 1/ 13
P(a 6) = 4 /52 = 1/13
Probability of either a 4 or a 6
P(a 4) + P(a 6)
1/13 + 1/13
= 2 / 13
The pair has one solution.
Answer: Option B.
<u>Explanation:</u>
A system of two linear equations can have one solution, an infinite number of solutions, or no solution. Systems of equations can be classified by the number of solutions. If a system has at least one solution, it is said to be consistent . If a consistent system has exactly one solution, it is independent.
If the system in two variables has one solution, it is an ordered pair that is a solution to both equations. In other words, when you plug in the values of the ordered pair it makes both equations TRUE.
It lets you see the pattern in the data
1024=16*2^n-1
1024/16=2^n-1
Log(1024/16)=(n-1)*log(2)
n=(log(1,024÷16)÷log(2))+1
n=7