Answer:
28+14.50+524.50+13.25= 580.25
Step-by-step explanation:
Add it all together.
Answer:
Total amount of fencing needed as an algebraic expression in terms of x is: <em>10x</em><em> </em><em>+</em><em> </em><em>3</em> .
Step-by-step explanation:
As it is given that each rectangle has the same dimensions, the dimensions of each rectangle must be: x units by 2x + 1 units.
Based on this, we can calculate the total amount of fencing needed.
Let width of each rectangle = x
Let length of each rectangle = 2x + 1
There are 4 widths and 3 lengths in total of fencing.
Therefore:
= 4 ( x ) + 3 ( 2x + 1 )
Expand:
= 4x + 6x + 3
Group like-terms:
= 10x + 3
N = 5m
n = m + 36
since n is equal to both the expression in m we can say:-
5m = m + 36
4m=36
m = 9
and n = 5*9 = 45
Answer:
1. 8 + 4 = 12 x 6 = 72
2. 9 + 6 = 15 x 4 = 60
3. 11 + 8 = 19 x 6 = 114
4. 4 + 6 = 10 x 5 = 50
5. 7 + 3 = 10 x 8 = 80
6. 8 + 12 = 20 x 9 = 180
7. 5 + 10 = 15 x 8 = 120
8. 19 + 13 = 32 x 10 = 320
9. 3 + 6 = 9 x 2 = 18
Area of a trapezoid:
Base 1 + Base 2 times Height times a half (basically dividing by 2).
