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Vikki [24]
3 years ago
11

What is the equivalent to (8 + 2)exponent 2+ (6-4)x3

Mathematics
2 answers:
grin007 [14]3 years ago
7 0

Answer:

67

Step-by-step explanation:

Sveta_85 [38]3 years ago
4 0

Answer:

I have made it in above picture

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The answer is go get a life
8 0
3 years ago
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Find the sum of 7a^3+14a+12 and -6a^3+12a^2-7
Rasek [7]

Answer:

a³+2a³+5

Step-by-step explanation:

7a³+14a+12+{-6a³}+12a²-7

=<u>7a³-6a³</u>+<u>14a+12a²</u>+<u>12-7</u>

=a³+2a³+5

4 0
3 years ago
In triangle ABC, EF=<br><br>a) 3cm<br>b) 2.5cm<br>c) 4cm<br>d) none of these​
zalisa [80]

Answer:

AE/AB = EF/BC

4cm/ 8cm = EF/ 5cm.....(Criss cross)

EF = 5 x 4/8

EF = 2.5 cm

4 0
3 years ago
(4y^2-3y+2)+(5y+12y-4)-(13y^2-6y+20)
Andrews [41]

Answer:

-(9 y^2 - 20 y + 22) or if you need y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

Step-by-step explanation:

Simplify the following:

-(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2

Grouping like terms, -(13 y^2 - 6 y + 20) + 4 y^2 + 12 y + 5 y - 3 y - 4 + 2 = -(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4):

-(13 y^2 - 6 y + 20) + 4 y^2 + (-3 y + 5 y + 12 y) + (2 - 4)

-3 y + 5 y + 12 y = 14 y:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + (2 - 4)

2 - 4 = -2:

-(13 y^2 - 6 y + 20) + 4 y^2 + 14 y + -2

-(13 y^2 - 6 y + 20) = -13 y^2 + 6 y - 20:

-13 y^2 + 6 y - 20 + 4 y^2 + 14 y - 2

Grouping like terms, 4 y^2 - 13 y^2 + 14 y + 6 y - 20 - 2 = (-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2):

(-13 y^2 + 4 y^2) + (6 y + 14 y) + (-20 - 2)

4 y^2 - 13 y^2 = -9 y^2:

-9 y^2 + (6 y + 14 y) + (-20 - 2)

6 y + 14 y = 20 y:

-9 y^2 + 20 y + (-20 - 2)

-20 - 2 = -22:

-9 y^2 + 20 y + -22

Factor -1 out of -9 y^2 + 20 y - 22:

Answer: -(9 y^2 - 20 y + 22)

______________________________________________

Solve for y:

-9 y^2 + 20 y - 22 = 0

Divide both sides by -9:

y^2 - (20 y)/9 + 22/9 = 0

Subtract 22/9 from both sides:

y^2 - (20 y)/9 = -22/9

Add 100/81 to both sides:

y^2 - (20 y)/9 + 100/81 = -98/81

Write the left hand side as a square:

(y - 10/9)^2 = -98/81

Take the square root of both sides:

y - 10/9 = (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

y = 10/9 + (7 i sqrt(2))/9 or y - 10/9 = -(7 i sqrt(2))/9

Add 10/9 to both sides:

Answer: y = 10/9 + (7 i sqrt(2))/9 or y = 10/9 - (7 i sqrt(2))/9

4 0
3 years ago
Combine like terms <br> x+x-x+y+y+y-z+z-z
stiks02 [169]

Answer:

X^3 x Y^3 x Z^3

Step-by-step explanation:

3 0
3 years ago
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