1. userVal < 0 ? "negative" : "positive"
2. updateDirection == 1 ? numUsers++ : numUsers--;
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I haven't seen your lesson, but I would:
- Not use PPTP, but rather OpenVPN or equivalent
- Consider using client certificates
- Consider using a token generator (a piece of hardware that generates access codes).
Answer:
on the first one pixels on the second i think it is feathering
Answer:
ensemble I think I'm pretty sure