True. That data is called binary
Cells are identified by the Cell Name (or Reference, which is found by combining the Column Letter with the Row Number. For example the cell in Column "C" in Row "3" would be cell C3. Cells may contain Labels, Numbers, Formulas or Functions. Cell Name: By default, the name of a cell is the cell reference.
Hope this helps
Answer:
import re
def country_capita():
#opens file
file=open("inputfile.txt", "r")
dictionary=dict()
#reads line by line
for line in file.readlines():
# substitutes for multiple space a single space
line = re.sub(r"[\s]{2, }", ' ', line)
list=[]
#splits line on space
list=line.split(" ")
#put into dictionary
dictionary[list[1]]=list[2]
# get input
while True:
choice=input("Enter the country name or quit to exit: ")
if choice=="quit":
break
elif choice in dictionary.keys():
print(dictionary[choice])
else:
print("Invalid Country")
country_capita()
Explanation:
Using python to code this program. First we, (line 1) import the re module which offers us a set of functions that allows us to search a string for a match. ((line 2) Next we define a function country_capita() that will open rawdata_2004.txt, read the information within line by line and create a dictionary list. The we create a while loop with conditional statements that prompt the user to enter country names, print the corresponding values and stops when the user enters quit.
Answer:
i) The time taken for 1500 records = 15 seconds.
ii) The time taken for 1500 records = 50 seconds.
Explanation:
A is an O(n) algorithm.
An algorithm with O(n) efficiency is described as a linearly increasing algorithm, this mean that the rate at which the input increases is linear to the time needed to compute that algorithm with n inputs.
From the question, it is given that for 1000 records, the time required is: 10 seconds.
Algorithm time taken is O(n)
Hence,
1) For 1,500 records
=> 10/1000 = x/1500
=> 10x1500/1000 = x
x = 15 seconds
Thus, the time taken for 1500 records = 15 seconds.
2) For 5,000 records
=> 10/1000 = x/5000
=> 10x5000/1000 = x
x = 50 seconds
Thus, the time taken for 1500 records = 50 seconds.
