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patriot [66]
3 years ago
15

What is equivalent to radical 40

Mathematics
1 answer:
Lana71 [14]3 years ago
5 0

Answer:

2sqrt(10)

Step-by-step explanation:

radical 40

I rewrite this as sqrt(40)  It means the same thing

sqrt(40)

sqrt(4*10)

We know that sqrt(a *b) = sqrt(a) sqrt(b)

sqrt(4) sqrt(10)

2sqrt(10)

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What is the value of x? please help me! <br><br> A. 43<br> B. 62<br> C. 105<br> D. 115
Valentin [98]

Answer:

C

Step-by-step explanation:

x is the exterior angle of angle EFG while EFG = 180 - 62 - 43 = 75

—> x = 180 - 75 = 105

6 0
2 years ago
A student guesses on every question of a multiple choice test that has 8 questions
astraxan [27]
Ok? Where’s the rest of the question.
7 0
3 years ago
PLEASE, I REALLY NEED YOUR HELP!!
Delicious77 [7]

Answer:

|x-5|=2

Step-by-step explanation:

1- Find the mid value between the given numbers 3 and 7

(3+7)/2= 10/2 = 5

2- Find the difference btween the mid value (5) and any of the two given numbers (3 or 7). Use the absolute value for the difference.

|5-3|= 2 or |7-5|=2

3- Arrange the absolute equation like this:

|x-mid value from step 1|= absolute difference from step 2

|x-5|=2

4- Double check the answer with the given values 3 and 7 using our equation |x-5|=2

|3-5|=2 correct

|7-5|=2 correct

7 0
2 years ago
Example:
Aleonysh [2.5K]

Answer:

AB // CD and AD // BC, then ABCD is a parallelogram

Step-by-step explanation:

Step 2: Show AD // BC

A = (-3 , 3) and D = (0 , 0)

Find the slope of AD

m_{AD}=\frac{0-3}{0--3}=\frac{-3}{3}=-1

B = (2 , 5) and C = (5 , 2)

m_{BC}=\frac{2-5}{5-2}=\frac{-3}{3}=-1

The slope of AD = the slope of BC

So AD // BC because they have the same slope

Step 3:

Each two opposite sides are parallel in quadrilateral ABCD

So the quadrilateral is a parallelogram

8 0
3 years ago
April shoots an arrow upward at a speed of 80 ft/sec from a platform of 25 ft. High. The pathway of the arrow can be represented
soldi70 [24.7K]

Answer:

125feet

Step-by-step explanation:

Given the equation that modeled the height expressed as h = -16t^2 + 80t + 25, where h is the height and t is the time in seconds.

The arrow reaches the maximum height at dh/dt = 0

dh/dt = -32t + 80

0= -32t+80

32t = 80

t = 80/32

t = 2.5secs

substitute t = 2.5 into the formula;

h = -16t^2 + 80t + 25

h = -16(2.5)^2 + 80(2.5) + 25

h = -16(6.25)+225

h = -100+225

h = 125

Hence the maximum height the arrow reaches is 125feet

4 0
2 years ago
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