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Alika [10]
3 years ago
10

2 lines form intersecting at a right angle a. form a line b. are parallel b. are perpendicular c. form a ray​

Mathematics
1 answer:
Nonamiya [84]3 years ago
5 0
Two lines intersecting at a right angle would be perpendicular. Parallel lines do not cross or touch each other, and rats don’t form right angles. Perpendicular lines are horizontal and vertical crossing together to form a right angle.

Hope this helps!
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Please, help me on this question, guys! I know the answer for (a) so I'll write down, too. For (b) I tried "$89,000 because that
Alexeev081 [22]
Let x be a random variable representing the price of a Congo-imported black diamond. Let the higher price be p. Then,
P(x < p) = P(x < (p - mean)/sd) = P(x < (p - 60,430)/21,958.08) = P(z < 2)
Therefore,
(p - 60,430)/21,958.08 = 2
p - 60,430 = 2 x 21,958.08 = 43,916.16
p = 34,916.16 + 60,430 = 104.346.16

Therefore, The required price is $104,346.16
7 0
3 years ago
(2 5/6)(6)+(-1 1/2)(1.5)-(1/16)
Jet001 [13]
Now I’m ngl my math might be wrong but I ended up with 1131/48
As a decimal I got 23.6
4 0
3 years ago
What is the value of x which proves that the runways are parallel? What is the measure of the larger angle? (evidently the answe
romanna [79]
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3 0
3 years ago
Which could be the first step in simplifying this expression? Check all that apply. (x cubed x Superscript negative 6 Baseline)
PtichkaEL [24]

Answer:

(x^{-3} )^{2}

x^6 x^{-12}

Step-by-step explanation:

(x^{3} x^{-6} )^{2} is the expression given to be solved.

First of all let us have a look at <u>3 formulas</u>:

1.\ p^a \times p^b = p^{(a+b)}\\2.\ (p^a \times q^b)^c = (p^{a})^c \times (q^{b})^c\\3.\ (p^a)^b = p^{a\times b}

Both the formula can be applied to the expression((x^{3} x^{-6} )^{2}) during the first step while solving it.

<u>Applying formula (1):</u>

(x^{3} x^{-6} )^{2}

Comparing the terms of (x^{3} x^{-6} ) with p^a \times p^b

p=x, a =3, b=-6

\Rightarrow x^{3+(-6)}\\\Rightarrow x^{3-6}\\\Rightarrow x^{-3}

So, (x^{3} x^{-6} )^{2} is reduced to (x^{-3} )^{2}

<u>Applying formula (2):</u>

Comparing the terms of (x^{3} x^{-6} )^{2} with (p^a \times q^b)^c

p=q=x, a =3, b=-6, c=2

\Rightarrow (x^{3})^2\times (x^{-6})^2\\\text{Applying Formula (3)}\\x^6 x^{-12}

So, (x^{3} x^{-6} )^{2} is reduced to x^6 x^{-12}.

So, the answers can be:

(x^{-3} )^{2}

x^6 x^{-12}

8 0
3 years ago
There are
rusak2 [61]

Answer:

14,000 decigrams

Step-by-step explanation:

Hope this helps

(nice porygon-z pfp lol)

5 0
3 years ago
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