After a little manipulation, the given diff'l equation will look like this:
e^y * dy = (2x + 1) * dx.
x^2
Integrating both sides, we get e^y = 2------- + x + c, or e^y = x^2 + x + c
2
Now let x=0 and y = 1, o find c:
e^1 = 0^2 + 0 + c. So, c = e, and the solution is e^y = x^2 + x + e.
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Answer:
Let 'x' and 'y' be two different numbers.
Leila says that 75% of a number will always be greater than 50% of a number. The inequality that represents this statement is the following:
0.75x > 0.5y
Let x = 100 and y=200. We have that:
0.75(100) > 0.5(200)
75 > 100 ❌ INCORRECT ❌
Given that we found a case in which 75% of a number is not greater than 50% of a number, we can conclude that Leila's claim is incorrect.
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