The quadratic equation x2 + mx + q = 0, where m and q are real numbers, has the complex root a + bi.?
1 answer:
Remember the quadratic formula determinant?
If b^2 -4ac < 0, a complex root exists.
So for this problem, m^2 - 4q is the determinant, and if less than 0, is complex.
So a=-m/2 and b=(1/2)SQRT(m^2 - 4q)
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