Answer:Para pasar el número decimal 1.83333 a fracción, siga los siguientes pasos:
Paso 1: Escriba el número como una fracción de 1 (uno):
1,83333 = 1,83333/1
Paso 2: Multiplica simultáneamente el numerador y el denominador por 10 tantas veces cuánto los dígitos después de la coma (separación entre la parte entera y la parte fraccionaria del número):
Como tenemos 5 números después de la coma, multiplique el numerador y el denominador por 100000. Así,
1,83333/1 = (1,83333 x 100000)/(1 x 100000) = 183333/100000.
Tenga en cuenta que multiplicar por 10 es el mismo que desplazar la coma a la derecha una posicion.
Una vez que esta fracción es irreductible, es decir, está en forma reducida, ya no podemos simplificarla. La respuesta es la fracción anterior.
Como el numerador es mayor que el denominador, tenemos una fracción IMPRORIA, entonces podemos expresarla como un NÚMERO separación, así 183333/100000 también es igual a 1 83333/100000 cuando se representa por un número mixto.
Step-by-step explanation:
Answer:
Hypergeometric distribution
Step-by-step explanation:
the hypergeometric distribution is a probability distribution that is discrete. It describes the probability of success without replacement, from a finite number of objects.
Hypergeometric distribution is used for relatively small population without replacements.
This shows that it will take the particle 23 secs to meet.
The distance travelled by each particle is 50cm
If two particles are projected simultaneously towards each other from opposite ends of a straight horizontal tube,
The first particle distances are 97cm, 93cm, 89cm... every 2secs
This form an arithmetic sequence and the nth term is expressed as:
Tn = a + (n - 1)d
a is the first term = 97
d is the common difference = 4
Substitute
Tn = 97+(n - 1)(4)
Tn = 97 + 4n -4
Tn = 4n + 93
Similarly for the distances 49 cm, 47 cm, 45cm .....
This also forms an arithmetic sequence and the nth term is expressed as:
Tn = a + (n - 1)d
a is the first term = 49
d is the common difference = 2
Substitute
Tn = 49+(n - 1)(2)
Tn = 49 + 2n -2
Tn = 2n + 47
For the particles to meet, this means that 4n + 93 = 2n + 47
4n - 2n = 47 - 93
2n = -46
n = -23
This shows that it will take the particle 23 secs to meet.
To get the distance travelled by each particle
Tn = 4n + 93
T2 = 4(2) + 93
T2 = 101
For the other sequence;
Tn = 2n + 47
T2 = 2(2) + 47
T2 = 51
Taking the difference;
D = 101 - 51 = 50cm
Hence the distance travelled by each particle is 50cm
Learn more here: brainly.com/question/13989292
Answer:
26 pints
Step-by-step explanation:
1 quart = 2 pints
13*2=26
Other factors may appear when 'r', 't', and 'e' get certain values.
But the only factors you can count on, that don't depend on the
values of 'r', 't', and 'e' and <em>always</em> work, are <em>(r + t)</em> and <em>'e'</em> .
