I think the answer might be A or D but most likely it's D
This is the graph with the answers in it. I searched it online and got the answer
Answer:
The red team is expected to win 6 fewer games than the blue team
Step-by-step explanation:
In this question, we are concerned with calculating the number of games the red team is expected to win less than what the blue team will win, given the probability of wining of each of the teams and the total number of games
To calculate the total number of games each team is expected to win, what we do is to multiply the probability of wining of each of the teams by the total number of games
For the red team , the probability of wining P(r) = 0.3
The total number of games expected to be won is mathematically equal to 0.3 × 120 = 36 games
For the blue team , the probability of wining P(b) = 0.35
The total number of games expected to be won is mathematically equal to 0.35 × 120 = 42 games
The number of games fewer that the red team is expected to win = number of games expected to be won by the blue team - number of games expected to be won by the red team = 42 games - 36 games = 6 games
Answer: 
and 
Step-by-step explanation:
In sampling distribution of 
.
The mean and standard deviation of the sampling distribution of p is given by :-
, where p= population proportion and n= sample size.
Let p be the population proportion of unmarried couples in the United States are mixed racially or ethnically.
As per given , we have
n = 100
p= 14% =0.14
Then, the mean and standard deviation of the sampling distribution of p will be :
Hence, the required answer : and
