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Hatshy [7]
3 years ago
8

Drew 2 two-dimensional shapes that had 8 angles in all

Mathematics
1 answer:
san4es73 [151]3 years ago
3 0
I think you want us to draw a <span>two-dimensional shape that had 8 angles total correct? Well here's what I think:

Octagon:



</span>

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What is the measurement of
goldfiish [28.3K]

Answer:

60

Step-by-step explanation:

All the sides are equal, which makes it an equilateral triangle.

That means all the angles are equal

180/3 = 60

Angle A is 60 degrees

7 0
3 years ago
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La ecuación de la recta que pasa por el punto P(1,3) y es paralela a la recta
Ne4ueva [31]

Answer:  No puedo responder a esto sin que me muestres el problema.

3 0
2 years ago
Divide (24x^2-16x+18)÷(4x+2)
Aleksandr [31]

Answer:

6x-7+32/4x+2

Step-by-step explanation:

Divide using polynomial division

3 0
3 years ago
At a canning facility, a technician is testing a machine that is supposed to deliver 250 milliliters of product. The technician
Serhud [2]

Answer:

The value of the test statistic is t = 1.97

Step-by-step explanation:

The null hypothesis is:

H_{0} = 250

The alternate hypotesis is:

H_{1} \neq 250

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the null hypothesis value, \sigma is the standard deviation and n is the size of the sample.

In this problem:

X = 251.6, \mu = 250, \sigma = 5.4, n = 44

So

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{251.6 - 250}{\frac{5.4}{\sqrt{44}}}

t = 1.97

The value of the test statistic is t = 1.97

4 0
3 years ago
What are all values of x for which the series shown converges? ​
adoni [48]

Answer:

One convergence criteria that is useful here is that, if aₙ is the n-th term of this sequence, then we must have:

Iaₙ₊₁I < IaₙI

This means that the absolute value of the terms must decrease as n increases.

Then we must have:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}}

We can write this as:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2 )^{n+1}}{(n + 1)*3^{n+1}} = \frac{(x -2)^n}{(n + 1)*3^n} * \frac{(x - 2)}{3}

If we assume that n is a really big number, then:

n + 1 ≈ 1

And we can write:

\frac{(x -2)^n}{n*3^n} > \frac{(x -2)^n}{(n)*3^n} * \frac{(x - 2)}{3}

Then we have the inequality

1 > (x - 2)/3

And remember that this must be in absolute value, then we will have that:

-1 < (x - 2)/3 < 1

-3 < x - 2 < 3

-3 + 2 < x < 3 + 2

-1 < x < 5

The first option looks like this, but it uses the symbols ≤≥, so it is not the same as this, then the correct option will be the second.

5 0
2 years ago
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