A sample of marble has a volume of 6 cm3 and a density of 2.76 g/cm3. What is its mass?
2 answers:
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Answer:
6. O+ to A+ donors = 90 to 45; 90 : 45 and 90/45
7. AB- donors to AB+ donors = 4 to 6; 4 : 6 and 4/6
8. B+ to total donors = 20 to 195; 20 : 195 and 20/195
9. O- donors to A- donors = 9 to 21; 9 : 21 and 9/21
10. B- donors to B+ donor = 0 to 20; 0 : 20 and 0/20
11. O- donors to total donors = 9 to 195; 9 : 195 and 9/195
12. A+ donors and B+ donors to AB+ donors = 65 to 6; 65 : 6 and 65/6
13. A- donors and B- donors to AB- donors = 21 to 4; 21 : 4 and 21/4
14. the ratio 90/9 is a comparison of O+ donors to O- donors
Step-by-step explanation:
A ratio is a relationship where for every x unit of one quantity there are y units of another quantity. A ratio can be written in three ways:
x to y
x:y, or
x/y
For the given questions;
6. O+ to A+ donors = 90 to 45; 90 : 45 and 90/45
7. AB- donors to AB+ donors = 4 to 6; 4 : 6 and 4/6
8. B+ to total donors = 20 to 195; 20 : 195 and 20/195
9. O- donors to A- donors = 9 to 21; 9 : 21 and 9/21
10. B- donors to B+ donor = 0 to 20; 0 : 20 and 0/20
11. O- donors to total donors = 9 to 195; 9 : 195 and 9/195
12. A+ donors and B+ donors to AB+ donors
A+ donors and B+ donors to = 45 + 20 = 65
therefore, A+ donors and B+ donors to AB+ donors = 65 to 6; 65 : 6 and 65/6
13. A- donors and B- donors to AB- donors
A- donors and B- donors = 21 + 0= 21
therefore, A- donors and B- donors to AB- donors = 21 to 4; 21 : 4 and 21/4
14. O+ donors = 90; O- donors = 9
therefore, the ratio 90/9 is a comparison of O+ donors to O- donors
