Answer:

Step-by-step explanation:
Let's re-write the equations in order to get the variables as separated in independent terms as possible \:
First equation:

Second equation:

Third equation:

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

Now we use this value for "x" back in equation 1 to solve for "y":

And finally we solve for the third unknown "z":

It would be 18 have a great day
Pretend to (or actually) cut out the given image, stick a pin in point P so it cannot move, and rotate the cutout up and to the left around point P about 1/8 of the way around the circle. The result of doing that is the picture you're looking for.
Answer:
10 meters is equivalent to 1000 cm and 0.01 kilometers
Step-by-step explanation: