4 years ago

Which is equivalent to radical 10 ^3/4

Mathematics

1 answer:

egoroff_w [7]4 years ago

3 0

Cuberoot(10)^4 is the answer

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Answer:

Step-by-step explanation:

From the given table, we have:

$y_{2}=4x^2$

⇒ $a=4(1)^2$

⇒ $a=4$

$y_{3}=4^x$

⇒ $b=4^1$

⇒ $b=4$

$y_{1}=4x$

⇒ $c=4(2)$

⇒ $c=8$

$y_{3}=4^x$

⇒ $d=4^2$

⇒ $d=16$

$y_{1}=4x$

⇒ $e=4(3)$

⇒ $e=12$

$y_{2}=4x^2$

⇒ $f=4(3)^2$

⇒ $f=36$ and

$y_{3}=4^x$

⇒ $g=4^3$

⇒ $g=64$

Therefore, the value of a,b,c,d,e,f and g is 4,4,8,16,12,36 and 64 respectively.

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3 years ago

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1. f(x)=x, g(x)=x+2<br> What happened from f(x) to g(x)?

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Answer: a horizontal shift of 2

Step-by-step explanation:

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3 years ago

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saveliy_v [14]

$\displaystyle\\\text{The equation is:}\\\\13^2-x^2=15^2-(14-x)^2\\\\13^2-x^2=15^2-(14^2-28x+x^2)\\\\13^2-x^2=15^2-14^2+28x-x^2)\\\\-x^2+x^2-28x=15^2-14^2-13^2\\\\-28x=225-196-169\\ \\-28x=-140~~~\Big|~\cdot(-1)\\\\28x=140\\\\x=\frac{140}{28}\\ \\\boxed{\bf x=5}$

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3 years ago