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german
3 years ago
9

How do I solve for x?

Mathematics
1 answer:
saveliy_v [14]3 years ago
4 0

 

\displaystyle\\\text{The equation is:}\\\\13^2-x^2=15^2-(14-x)^2\\\\13^2-x^2=15^2-(14^2-28x+x^2)\\\\13^2-x^2=15^2-14^2+28x-x^2)\\\\-x^2+x^2-28x=15^2-14^2-13^2\\\\-28x=225-196-169\\ \\-28x=-140~~~\Big|~\cdot(-1)\\\\28x=140\\\\x=\frac{140}{28}\\ \\\boxed{\bf x=5}



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