Question

A fruit bowl contains 3 apples, 5 pears, and 6 oranges. Kayla selects 2 fruits at random without replacement. What is the probability that she selects an apple, then an orange?
9.9%

9.2%

25%

19.8%

Answer 1

Answer:

9.9%

Step-by-step explanation:

we know that

The probability of an event is the ratio of the size of the event space to the size of the sample space.  

The size of the sample space is the total number of possible outcomes  

The event space is the number of outcomes in the event you are interested in.  

so  

Let

x------> size of the event space

y-----> size of the sample space  

so

$P=\frac{x}{y}$

Part 1) Find the probability that she selects an apple first

In this problem we have

$x=3$  ----> total number of apples

$y=3+5+6=14$  ---> total number of fruits

substitute

$P=\frac{3}{14}$

Part 2) Find the probability that then she selects an orange

In this problem we have

$x=6$  ----> total number of oranges

$y=2+5+6=13$  ---> total number of fruits

substitute

$P=\frac{6}{13}$

Part 3) Find the probability that she selects an apple, then an orange

Multiply both probabilities

$P=(\frac{3}{14})(\frac{6}{13})=\frac{18}{182}=0.0989$

Convert to percentage

$0.0989*100=9.89\%=9.9\%$

Answer 2

Answer:

9.9% is correct.

Step-by-step explanation: