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3 years ago

Which of the following is correctly written in Standard Form?

Mathematics

1 answer:

Marta_Voda [28]3 years ago

8 0

9514 1404 393

Answer:

(b) 4x- 3y = 6

Step-by-step explanation:

Standard form is ...

ax +by = c

where a, b, c are mutually prime integers and a > 0. (If a=0, then b>0.)

A: slope-intercept form with variables on both sides of the equal sign.

B: standard form

C: coefficients aren't integers

D: coefficients aren't integers; leading coefficient is negative.

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-3|9x-7|=2 Find the answer for x

labwork [276]

<h2>Solving Equations with Absolute Expressions</h2><h3>Answer:</h3>

No Solutions

<h3>Step-by-step explanation:</h3>

Given:

$-3|9x -7| = 2$

Rewriting the given equation:

$-3|9x -7| = 2 \\ |9x -7| = -\frac{2}{3}$

We have to realize that the right side of the equation, $|9x -7|$ , will always be positive no matter what real values of $x$ (because we're taking the absolute value of the expression) and we are equating it to a negative constant number, $-\frac{2}{3}\\$ . Something that is always positive will never be negative so there's no value for $x$ that satisfies the solution.

$\rule{6.5cm}{0.5pt}$

You may not read the following passage that I have written.

$\rule{6.5cm}{0.5pt}$

Solving by positive of the expression:

$9x -7 = -\frac{2}{3} \\ 9x = -\frac{2}{3} +7 \\ 9x = -\frac{2}{3} +\frac{21}{3} \\ 9x = \frac{19}{3} \\ 9x \times \frac{1}{9} = \frac{19}{3} \times \frac{1}{9} \\ x = \frac{19}{27}$

Solving by the negative of the expression:

$-(9x -7)= -\frac{2}{3} \\ 9x -7 = \frac{2}{3} \\ 9x = \frac{2}{3} +7 \\ 9x = \frac{2}{3} +\frac{21}{3} \\ 9x = \frac{23}{3} \\ 9x \times \frac{1}{9} = \frac{23}{3} \times \frac{1}{9} \\ x = \frac{23}{27}$

Checking: $x = \frac{19}{27}\\$

$-3|9(\frac{19}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{19}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|-\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{19}{27}\\$ is an extraneous solution.

Checking: $x = \frac{23}{27}\\$

$-3|9(\frac{23}{27}) -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -7| \stackrel{?}{=} 2 \\ -3|\frac{23}{3} -\frac{21}{3}| \stackrel{?}{=} 2 \\ -3|\frac{2}{3}| \stackrel{?}{=} \\ -3(\frac{2}{3}) \stackrel{?}{=} 2 \\ -2 \stackrel{?}{=} 2 \\ -2 \neq 2$

$x = \frac{23}{27}\\$ is an extraneous solution.

8 0

3 years ago

Is 0 a complex, pure imaginary, and a nonreal complex number?

lisabon 2012 [21]

Answer:

Step-by-step explanation:

First, 0 doesn't have any i values, so 0 is not pure imaginary.

Also, 0 is indeed a real number, so it is not a "non-real complex number."

Therefore, the only option left is that 0 is a complex number, and 0 is indeed a complex number.

The answer is A.

7 0

3 years ago

What is the answer to 5 (x - 1) + 3 = 13

AleksAgata [21]

Step-by-step explanation: To solve for x when the equation includes an exponent, start by isolating the term with the exponent. Then, isolate the variable with the exponent by dividing both sides by the coefficient of the x term to get your answer. If the equation has fractions, start by cross-multiplying the fractions.

8 0

3 years ago

Read 2 more answers

“Bishon needs to sell at least 0.3 of his Collin sports card to make room for new cards.is 3/20 of his collection enough? Explai

Darya [45]

Answer:

I dont know But maybe the answer is No

Step-by-step explanation:

0.3 is 30% and if 1/10 is 10% then 2/20 must be 10% because 5% is 1/20

so maybe 3/20 is only 15%

I hope this helps :)

Sorry if it dosent i suck at explaining things ; - ;

3 0

3 years ago

Flor and Mo both donated money to the same charity. Flor gave three times as much as Mo. Between the two of them, they donated $

BlackZzzverrR [31]

To answer this question, you would divide the total by 3 to find the money that Mo gave. so 280/3= $93.33. I would check my math, just to be safe, however, I hope this helps you out.

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3 years ago