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MissTica
3 years ago
14

Baby's crib would be about how long? 1 m 2 m 10 m 1 km question #8truefalse score: the length of a small object, such as a penci

l, would be measured in kilometers. truefalse question #9multiplechoice score: 5 m is equal to: 500 mm5,000 mm50 cm5,000 cm question #10multiplechoice score: the height of a coffee mug would be about: 500 mm8 cm20 cm0.1 km
Mathematics
2 answers:
Dafna1 [17]3 years ago
7 0
A baby's crib would be about 1 m
False
5m=5,000mm
8cm
cricket20 [7]3 years ago
6 0

Answer:

1. Baby's crib would be about how long? 1 m 2 m 10 m 1 km

It will be about 1 m or approx 3 feet.

It cannot be 2 meters as it will be more than 6 feet and babies are not that much bigger.

2. The length of a small object, such as a pencil, would be measured in kilometers.

False. Rather a pencil can be measured in cm or inches.

3.  5 m is equal to: 5,000 mm

1 meter = 1000 mm

So, 5 meter = 1000\times5=5000 mm

4. The height of a coffee mug would be about: 8 cm

0. 1 km is irrelevant, 500 mm is equal to 50 cm that is also wrong as coffee mugs at most 10 cm.

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6

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there are 6 -10's in -60 feet

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Is 31 and composite or prime
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31 is a prime number.
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What is the length of side x in the above right triangle​
nataly862011 [7]

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3 years ago
[[ ANSWER ASAP ]]
zhenek [66]

Option B:

The relationship between angle j and angle k is j° + k° = 180°.

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Given JKLM is a parallelogram.

angle J and angle K are consecutive angles.

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<em>In parallelogram, the sum of the consecutive angles is 180°.</em>

⇒ m∠J + m∠K = 180°

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3 years ago
Solve for x 6x^2=2x-1
leva [86]

Answer:

\displaystyle x=\frac{1\pm i\sqrt{5}}{6}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Standard Form: ax² + bx + c = 0
  • Quadratic Formula: \displaystyle x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}

<u>Algebra II</u>

  • Imaginary Roots: √-1 = i

Step-by-step explanation:

<u>Step 1: Define</u>

6x² = 2x - 1

<u>Step 2: Rewrite</u>

  1. Subtract 2x on both sides:                    6x² - 2x = -1
  2. Add 1 to both sides:                               6x² - 2x + 1 = 0

<u>Step 3: Identify Variables</u>

a = 6

b = -2

c = 1

<u>Step 4: Solve for </u><em><u>x</u></em>

  1. Substitute [QF]:                       \displaystyle x=\frac{2\pm\sqrt{(-2)^2-4(6)(1)} }{2(6)}
  2. Exponents:                              \displaystyle x=\frac{2\pm\sqrt{4-4(6)(1)} }{2(6)}
  3. Multiplication:                         \displaystyle x=\frac{2\pm\sqrt{4-24} }{12}
  4. (Square Root) Subtract:         \displaystyle x=\frac{2\pm\sqrt{-20} }{12}
  5. Factor:                                    \displaystyle x=\frac{2\pm \sqrt{-1} \sqrt{20} }{12}
  6. Simplify:                                 \displaystyle x=\frac{2\pm 2i\sqrt{5} }{12}
  7. Factor GCF:                           \displaystyle x=\frac{2(1\pm i\sqrt{5} )}{12}
  8. Simplify:                                 \displaystyle x=\frac{1\pm i\sqrt{5}}{6}
3 0
3 years ago
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