3 years ago

Solve n^4-11n^2+30÷n^4-7n^2+10

1 answer:

8 0

Factor the numerator and denominator...

(n^4-5n^2-6n^2+30)/(n^4-2n^2-5n^2+10)

[n^2(n^2-5)-6(n^2-5)]/[n^2(n^2-2)-5(n^2-2)]

[(n^2-5)(n^2-6)]/[(n^2-5)(n^2-2)] notice the (n^2-5)s cancel out

(n^2-6)/(n^2-2)

We could further factor this because each is a difference of squares to:

[(n+√6)(n-√6)]/[(n+√2)(n-√2)

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Evaluate angles d and e, giving reason for your answer

Jobisdone [24]

Answer:

Ok so we know that the angle on top is 110 since the angle above is the same.

we also know that all the angle of the triangle will add up to 180 so

D+(180-E)+110=180

we also know that d and the angle directly across are the same so

180-110=70

70divide by 2 equals 35

now we subtratch 35 from 180 to get 145

E=145