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Dima020 [189]
2 years ago
7

On a quiz there are four-mulptiple choice questions worth 3 points each and two true/false questions worth 1 point​

Mathematics
1 answer:
Scilla [17]2 years ago
7 0

Answer:

15

Step-by-step explanation:

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Write fourteen billion in scientific notation
nikdorinn [45]

Answer:

3.4 x 107

Step-by-step explanation:

6 0
2 years ago
I need help completing this answer are you available
melomori [17]

Answer:

Step-by-step explanation:

7 0
2 years ago
Find the measure of the reference angle for an 11 radian<br> radian angle.
Vesnalui [34]

Answer:

  about 1.56637 radians ≈ 89.746°

Step-by-step explanation:

The reference angle in radians can be found by the formula ...

  ref angle = min(mod(θ, π), π -mod(θ, π))

Equivalently, it is ...

  ref angle = min(ceiling(θ/π) -θ/π, θ/π -floor(θ/π))×π

<h3>Application</h3>

When we divide 11 radians by π, the result is about 3.501409. The fractional part of this quotient is more than 1/2, so the reference angle will be ...

  ref angle = (1 -0.501409)π radians ≈ 1.56637 radians ≈ 89.746°

__

<em>Additional comment</em>

For calculations such as this, you need to use the most accurate value of pi available. The approximations 22/7 or 3.14 are not sufficiently accurate to give good results.

4 0
2 years ago
Express the quotient of z1 and z2 in standard form given that <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D%20-3%5Bcos%28%5C
Lesechka [4]

Answer:

Solution : -\frac{3}{4}-\frac{3}{4}i

Step-by-step explanation:

-3\left[\cos \left(\frac{-\pi }{4}\right)+i\sin \left(\frac{-\pi \:}{4}\right)\right]\:\div \:2\sqrt{2}\left[\cos \left(\frac{-\pi \:\:}{2}\right)+i\sin \left(\frac{-\pi \:\:\:}{2}\right)\right]

Let's apply trivial identities here. We know that cos(-π / 4) = √2 / 2, sin(-π / 4) = - √2 / 2, cos(-π / 2) = 0, sin(-π / 2) = - 1. Let's substitute those values,

\frac{-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right)}{2\sqrt{2}\left(0-1\right)i}

=-3\left(\frac{\sqrt{2}}{2}-\frac{\sqrt{2}}{2}i\right) ÷ 2\sqrt{2}\left(0-1\right)i

= 3\left(-\frac{\sqrt{2}i}{2}+\frac{\sqrt{2}}{2}\right) ÷ -2\sqrt{2}i

= \frac{3\left(1-i\right)}{\sqrt{2}}÷ 2\sqrt{2}i = -3-3i ÷ 4 = -\frac{3}{4}-\frac{3}{4}i

As you can see your solution is the last option.

3 0
3 years ago
A dilation with a scale factor of 1/3 is a reduction.
Natasha_Volkova [10]
That's true.
That will make the thing a third of its original size.
8 0
3 years ago
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