1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
topjm [15]
3 years ago
13

I WILL CASH APP 15 DOLLARS TO ANYONE WHO CAN COMPLETE MY TWO VIRTUAL MATH TESTS FOR GEOMETRY!! PLEASE COMMENT OR RESPOND TO THIS

!! I REALLY NEED HELP!!
Mathematics
1 answer:
nata0808 [166]3 years ago
7 0

Answer:

I will help

Step-by-step explanation:

You might be interested in
A box contains cards number 1-10. A card is drawn at random, then replaced, and a second card is drawn. What is the probability
aliina [53]
You would solve this by determining how many numbers from 1-10 can be multiples of 5.  That's obviously 5 and 10.  So that's 2/10 or reduced to 1/5.  Now the second question you have to find how many numbers from 1-10 are prime.  Prime is a number that can only be divided by 1 and itself.  So that would leave you with 1, 3, 5, 7.  I think where the trick comes into play is if you drew a 5 or 10 the first time, then you didn't place those cards back in the box, you couldn't draw them again.  So the answer would 4/10 or 2/5 if you could draw the 5 again.  Or I supposed if you had drew the 10 the first time and not the 5.  I assume however, they want you to exclude 5 and 10 because it was part of the first section of this equation.  So that would mean only 1, 3, and 7 or 3/10.
5 0
3 years ago
Ahhh helppp!
labwork [276]

Answer:D

Step-by-step explanation:

Function means that the pairs inside the [ ] should not have the same x value. since there are 2 pairs with 2 as the x value, you need to eliminate one of them

5 0
3 years ago
Solve for x. <br><br> 3x = 2/5
Elena-2011 [213]
X = 0.4/3
x = 13
if answer is wanted in decimal form.
6 0
4 years ago
Hope u can help me plz
svet-max [94.6K]

Step-by-step explanation:

Starting with the first one, we know that 3²=9 and 4²=16, so √10 is between 3 and 4. Similarly, √27 is a little over 5. √3 is close to 2, √2 is close to 1, and √9=3, so for simplicity, we can write this as \frac{3.something*5.something}{1.something*1.something*3}

The 3.something and the 3 kind of cross out, and we're left with 5.something over 2 1.somethings, which can be closer to 2 or 1, which is somewhat unclear -- therefore, our answer can be D or E, and we'll wait on this one

For the second one, we can cross out the √6s to get \frac{8\pi -6\pi }{2} =\pi -- π is a little greater than 3, so this is E, making the first one D

For the third one, we can cross out the √3 to get (3-2)/2 = 1/2, or A as it is between 0 and 1

For the last one, note the multiplication -- cross out the √3 to get (3*2√2)/6, and we get 6√2/6=√2, or C

3 0
4 years ago
Gorgi found a shoe pair for $35. She had a 30% discount. What is the price now?
White raven [17]

Answer:

$24.50

Step-by-step explanation:

$35 - 30% = $24.50.

Thus, that is the answer.

Hope this helps!

8 0
3 years ago
Read 2 more answers
Other questions:
  • Which of the following statements are true. Select all that apply
    11·2 answers
  • a ferris wheel rotates around in 30 seconds. the maximum height above theground is 55 feet and the minumum height above the grou
    9·2 answers
  • Solve each equation. Factor and use the zero product property to solve. Show all work algebraically.
    10·1 answer
  • Find the slope of the line
    14·2 answers
  • How do you do this problem?<br> Please show your work
    10·1 answer
  • Is 0.3 pie a rational or irrational
    15·2 answers
  • Pls answer ASAP i need help
    7·2 answers
  • You now know a lot about all the angles formed from two straight lines that intersect. You know which angles are congruent and w
    10·2 answers
  • Can someone please help me
    8·1 answer
  • HELP PLS ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎ ‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎‎
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!