Use the pythagorean theorem to solve this: a^2 + b^2 = c^2.
You already have a and b which are 3 and 4. Square them up and you will get 9 + 16 = c^2.
Add.
25 = c^2
Lastly, square root both sides.
5 = c
The length of AB is 5.
F(x)=x^3-9x
and
g(x)=x^2-2x-3
so you just need to divide f(x) by g(x)
Therefore:
f(x)/g(x) = (x^3-9x) / (x^2-2x-3)
and of course you need to factor these two function to see if some factor would cancel another
x^3-9x = x(x^2-9)=x(x-3)(x+3)
and
x^2-2x-3 = (x-3)(x+1)
Answer:
C. In y^2-y=6, 6 should have been subtracted on both sides first.
Step-by-step explanation:
It is a quadratic equation so you subtract the 6 and create
y^2-y-6=0
Then you factor it to:
(y-3)(y+2)=0
The solutions then are:
y-3=0, y=3 and y+2=0, y=-2
{-2,3}
Sorry, i dont know that one. i wish i could help ya
