m∠BCD= m∠ACB ÷ 2 = 134.76° ÷ 2 = 67.38°
Ok done. Thank to me :>
End of First Year (750/100)x12(3/5)=54 $750+54=804
End of Second Year (804/100)x12(3/5) = 58 $804+58=862
End Of Third Year (862/100)x12(3/5) = 62 $862+62=924
STOCK WORTH NOW = 924
The probability of you being the leadoff hitter is <span>8.3%.</span>
Explanation:
The number of possible rosters can be calculated with permutations, knowing that the coach can choose the first hitter among all 12 players, then the second hitter among the 11 players remaining and so on until the 9th hitter among the remaining 4 players.
Therefore:
Possible rosters = 12 × 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 = 79833600
The leadoff hitter is the first player in the batting order, therefore the number of possible rosters in which you are chosen as the first one is:
You leadoff = 1 <span>× 11 × 10 × 9 × 8 × 7 × 6 × 5 × 4 = 6652800
The probability of you being leadoff is:
P</span> = You leadoff / <span>Possible rosters
</span> = 6652800 / 79833600
= 1 / 12
= 0.08333
= 8.3%
Note that this is exactly the probability of you being chosen out of the 12 players of the team in a one-pick choice because it does not matter how the rest of the batting order is composed.
So here, ABCD is being inscribed in a circle, so ABCD is a cyclic quadrilateral (as inscribed in a circle) also, there exists a property of cyclic quadrilateral, i.e, the sum of opposite angles of a cyclic quadrilateral is 180°, so we can just write the following equation using this :




I think it is the answer b because I think it the right choice I think you should choose B ok have a great day.