Answer:
9.4 m/s
Step-by-step explanation:
We are given that
Height of pile driver above a pile =h=4.5 m
Acceleration due to gravity=
According to law of conservation of energy
K.E=Potential energy
Substitute the values
m/s
Hence, the velocity of pile driver as it hits the pile=9.4 m/s
<span>erry starts rowing at 2 pm from the west end of the lake, and Tao starts rowing from the east end of the lake at 2:05 pm.
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Terry DATA:
rate = 60 meter/min ; time = x min ; distance = r*t = 60x meters
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Tao DATA:
rate = 40 meter/min ; time = x-5 min ; distance = r*t = 40(x-5) meters
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If they always row directly towards each other at what time will the two meet?
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Equation:
dist + dist = 2000 meters
60x + 40(x-5) = 2000
20x = 1800
x = 90 minutes
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d. 1440
I'm guessing you mean hours in a school yr
8 hrs in a day x 180 days = 1440 hrs in 1 school yr
Answer:
∠FQD is 146°
Step-by-step explanation:
Because ∠P is on the same line as angle ∠Q, they are both corresponding angles meaning that they are equal so:
2x = 5x - 51
Add 51 to both sides of the equation:
2x + 51 = 5x - 51 + 51
2x + 51 = 5x
Subtract 2x from both sides:
2x - 2x + 51 = 5x - 2x
51 = 3x
Divide both sides by 3:
x = 17
Now we can calculate ∠FQE by substituting the known x into the equation:
5x-51
5(17) - 51 = 34
Now subtract this from 180 as all angles must add up to 180 on a straight line:
180 - 34 = 146
That means ∠FQD is 146°
Hope this helps!
Firstly you should add the like terms i.e. 5x + x. So The answer will be 6x + 2. If it requires you to factorise then take out the highest common factor i.e. 2. So factorised the answer will be 2(3x + 1).