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2 years ago

8

DO NOT SKIP!! Let’s see who’s smart enough to work out the problem if u get it correct I’ll mark u as BRAINLIEST SHOW THE WORK P

LEASE
Tell me what error did she make

1 answer:

ICE Princess25 [194]2 years ago

7 0

In year 10, the table says the population is 25,000

But if we plugged x = 10 into the equation Lucy got, then,

y = 600x + 25000

y = 600(10) + 25000

y = 6000 + 25000

y = 31000

Lucy's equation says that the population in year x = 10 should be y = 31000 instead of 25000. So this is one way to show that there is an error. The output from the equation isn't matching what the table shows.

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PLSSS HELP!! I need the answer m.

Alborosie

6578 i don’t know don’t ask me bit

3 0

3 years ago

Which expressionism equivalent to -60 / 5 select all that apply 60 divided by negitive 5 60 times 1/5 60 times negitive 1/5 Negi

GaryK [48]

Answer:

Equivalent expressions

A) $\frac{60}{-5}$

C) $60\times (-\frac{1}{5})$

Step-by-step explanation:

Given expression :

$\frac{-60}{5}$

Choices given :

A) $\frac{60}{-5}$

B) $60\times \frac{1}{5}$

C) $60\times (-\frac{1}{5})$

D) $-60\times (-\frac{1}{5})$

To find the equivalent expression.

We will first evaluate the given expression.

$\frac{-60}{5}$

⇒ $-12$ [Quotient of a negative dividend and a positive divisor is always negative]

Evaluating each choice to select the equivalents.

A) $\frac{60}{-5}$

⇒ $-12$ [Quotient of a positive dividend and a negative divisor is always negative]

B) $60\times \frac{1}{5}$

⇒ $\frac{60}{5}$

⇒ $12$

C) $60\times (-\frac{1}{5})$

⇒ $-\frac{60}{5}$ [Product of a positive and a negative is always a negative]

⇒ $-12$

D) $-60\times (-\frac{1}{5})$

⇒ $\frac{60}{5}$ [Product of two negatives is always a positive]

⇒ $12$

∴ We see that the choices A and C are equivalent.

7 0

3 years ago

Can someone help me with this math homework please!

Korolek [52]

Answer:

it is the second statement x⇒∞ Y⇒ ∞

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

An angle is five times its supplement. Find both angles.

noname [10]

The measure of the smaller angle is 30 degrees.
The measure of the larger angle is 150 degrees.

What I did:
supplementary angle=180 degrees.
<span>An angle is five times its supplement=180/6=
30
30*5=150
150+30=180

</span>

5 0

2 years ago

In the past, the average age of employees of a large corporation has been 40 years. Recently, the company has been hiring older

Viktor [21]

Answer:

$p_v =P(t_{(63)}>2.5)=0.0075$

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

Step-by-step explanation:

1) Data given and notation

$\bar X=45$ represent the mean height for the sample

$s=16$ represent the sample standard deviation for the sample

$n=64$ sample size

$\mu_o =40$ represent the value that we want to test

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean age is higher than 40 years, the system of hypothesis would be:

Null hypothesis: $\mu \leq 40$

Alternative hypothesis: $\mu > 40$

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{45-40}{\frac{16}{\sqrt{64}}}=2.5$

P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=64-1=63$

Since is a one right tailed test the p value would be:

$p_v =P(t_{(63)}>2.5)=0.0075$

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the mean age is significantly higher than 45 years at 5% of significance.

6 0

2 years ago