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olasank [31]
3 years ago
9

Find the volume and explain. Please answer ASAP.

Mathematics
1 answer:
Nana76 [90]3 years ago
4 0

Answer:

13.65ft^3

Step-by-step explanation:

the volume of any prism is base area* height

area of triangle is (bh)/2

2.6*7/2=9.1

9.1*1.5=13.65

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Help me please.. i don't wanna fail
TEA [102]

Answer:

Step-by-step explanation:

Cindy is correcy because on "Step 1:"  the multiplication was correctly distributed over the subtraction in paranthesis 5(x-2) = 5*x- 5*2 = 5x-10.

Henry was wrrong because he distributed 5 only over x and not over -2 as well 5(x-2) ≠ 5*x-2

5 0
2 years ago
In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and
Leviafan [203]

Answer:

A. (Table Attached)

B. (See Step 3)

C. 0.06 (See Step 4)

D. NOT independent (See Step 5)

Step-by-step explanation:

<h3 /><h3>STEP 1:</h3>

Name the probabilities:

p₁ = 0.02,   p₂ = 0.07,   p₃ = 0.91

q₁ = 1-p₁ = 0.98 ,   q₂ = 1-p₂ = 0.93 ,   q₃ = 0.09

Let X and Y be the number of bits with high and moderate distortion out of three.

<h3>STEP 2:</h3>

A.

The function will follow multinomial distribution:

f_{XY}(x,y) = P(X=x, Y=y) = \frac{3!}{x!y!(3-x-y)!} (p_1^x)(p_2^y)(p_3^{3-x-y})

Substitute the values and make a table.

TABLE IN ATTACHMENT

<h3>STEP 3:</h3>

B.

We calculate marginal distribution by:

P (X=x)= <em>∑</em> P(X=x,Y=y)

fx(x) can be found by adding all the probabilities in each row for different value of X

For X=0 , ∑P = 0.94157441

For X=1 , ∑P = 0.057624

For X=2 , ∑P = 0.001176

For X=3 , ∑P =0.000008

<h3>STEP 4:</h3><h3>C.</h3>

The mathematic expectation E is the sum of product of each possibility with its probabiity.

E(X)=<em>∑ </em>xP(X=x)

Find E(X):

E(X)= (0*0.9415744)+(1*0.057624)+(2*0.001176)+(3*0.000008)

E(X)=0.06

<h3>STEP 5:</h3>

Condition probability states:

P(A|B)=\frac{P(A,B)}{P(B)}

It can also be written as:

f_{Y|X=1}(y)=\frac{f_{XY}(1,y)}{f_x(1)}

Where f_x(1)\\ = 0.057624

Calculate the quotient:

Y|_{x=1} = 0 ,  f_{Y|_X=1 = 0.862245

Y|_{x=1} = 1 ,  f_{Y|_X=1 = 0.132653

Y|_{x=1} = 2 ,  f_{Y|_X=1 = 0.000510

Y|_{x=1} = 3 ,  f_{Y|_X=1 = 0

Find the dependency:

f_{XY}(y)=f_X(x)f_Y(y)

We found that

f_{Y|_X=1 = 0.862245

Calculate f_Y(1) from summing the column from the table

f_Y(1)=0.17428341+0.007644+0.000084\\f_Y(1)=0.18201141

Which are not equal.

Conclusion:

X and Y are NOT Independent

7 0
3 years ago
Need help in 31 and 33 thanks need ASAP
cricket20 [7]

Answer:

31: |8| +|18|=|26|

33: |2| +|9|=|11|

since these numbers are already positive, the numbers will stay the same just add the bars in front and after it.

4 0
3 years ago
I like ya cut g gottie
Sergeu [11.5K]
Answer= I like ya cut g because gottie
3 0
2 years ago
Read 2 more answers
7 girls audition for 12 roles in a school play. What is the probability that at least 2 of the girls audition for the same part?
Sophie [7]

Answer:

Step-by-step explanation:

This is one minus the probability that all the girls audition for different roles. The total number of ways of assigning roles to the girls is 12^7, because to each of the 7 girls, you have a choice of 12 roles.

Then if each girl is to receive a different role, then there are 12!/5! possibilities for that. If you start assigning roles to the girls, then for the first girl, there are 12 choices, but for the next you have to choose one of the 11 different ones, so 11 for the next, and then one of the 10 remaining for the next etc. etc., and this is 12*11*10*...*6 = 12!/(12-7)! =12!/5!

The probability that a random assignment of one of the 12^7 roles would happen to be one of the 12!/5! roles where each girl has a different role, is

(12!/5!)/12^7 = 12!/(12^7 5!)

Then the probability that two or more girls addition for the same part is the probability that not all the girls are assigned different roles, this is thus:

1 - 12!/(12^7 5!)

6 0
3 years ago
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