Answer: More the electronegativity difference, more polar will be the bond.
Explanation: The electronegativity is defined as the tendency of an element to attract a shared pair of electron towards itself in a chemical bond.
Polarity of the bond is described by the electronegativity difference between the elements making the bond. More the electronegativity difference, more polar is the bond.
The electronegativities of oxygen, hydrogen and nitrogen are:
For Oxygen : 3.44
For Hydrogen : 2.1
For Nitrogen : 3.04
In
Electronegativity difference between oxygen and hydrogen = (3.44 - 2.1) = 1.34
In
Electronegativity difference between nitrogen and hydrogen = (3.04 - 2.1) = 0.94
As, the Electronegativity difference between oxygen and hydrogen is more, therefore water molecule is more polar.
Answer:
1. NO and Br₂
2. 77
3. 8.8
Explanation:
Let's consider the following reaction.
2 NO(g) + Br₂(g) ⇄ 2 NOBr(g)
The equilibrium constant for this reaction is:
1. At this temperature does the equilibrium favor NO and Br₂, or does it favor NOBr?
Since Kc₁ < 1, the reactants are favored, that is, NO and Br₂.
2. Calculate Kc for 2 NOBr(g) ⇄ 2 NO(g) + Br₂(g)
The equilibrium constant is:
3. Calculate Kc for NOBr(g) ⇄ NO(g) + 1/2 Br₂(g)
The equilibrium constant is:
Answer: The percent ionization of in a 0.050 M
solution is 8.9 %
Explanation:
cM 0 0
So dissociation constant will be:
Give c= concentration = 0.050 M and = degree of ionisation = ?
Putting in the values we get:
percent ionisation =