Answer:
K.E = 25 J
Explanation:
Given data:
Mass of ball = 0.5 g
Velocity of ball = 10 m/s
Kinetic energy = ?
Solution:
Formula:
K.E = 1/2 mv²
m = mass
v = velocity
Now we will put the values in formula.
K.E = 1/2 mv²
K.E = 1/2× 0.5kg × (10m/s)²
K.E = 1/2 ×0.5kg × 100m²/s²
K.E = 25 Kg.m²/s²
Kg.m²/s² = J
K.E = 25 J
Answer:
3300.85 g
Explanation:
Given data:
Mass of ZnCl₂ produced = ?
Mass of H₂ produced = 49.8 g
Solution:
Chemical equation:
Zn + 2HCl → ZnCl₂ + H₂
Number of moles of H₂:
Number of moles = mass/molar mass
Number of moles = 49.8 g/ 2.056 g/mol
Number of moles = 24.22 mol
Now we will compare the moles of H₂ with ZnCl₂ form balance chemical equation.
H₂ : ZnCl₂
1 : 1
24.22 : 24.22
Mass of ZnCl₂:
Mass = number of moles × molar mass
Mass = 24.22 × 136.286 g/mol
Mass = 3300.85 g
There are two N≡N bonds and three H–H bonds are in reactants.
Given:
The reaction between nitrogen gas and hydrogen gas.
To find:
Bonds on the reactant side
Solution:
Reactants in the reaction = 
The bond between nitrogen atoms in single 
molecule = N≡N (triple bond)
Then in two molecules = 2 N≡N (triple bonds)
The bond between hydrogen atoms in single 
molecule = H-H (single bond)
Then in three molecules = 3 H-H (single bonds)
Product in the reaction =
The bonds between nitrogen and hydrogen atoms in single molecule = 3 N-H (single bond)
Then in two molecules = 6 N-H (single bonds)
So, there are two N≡N bonds and three H–H bonds are in reactants.
Learn more about reactants and products here:
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