Answer:
1/6
Step-by-step explanation:
Given that :
Total surveyed (u) = 120
n(Cane's chicken fingers) = 50
n(Layne's chicken fingers) = 80
n(do not like either) = 10
a)
What is the probability that someone surveyed likes both Raising Cane's and Layne's chicken fingers?
n(Cane's n Layne's) = 20
u = 120
P = required outcome / total possible outcomes
P(Layne's and Cane's chicken) = [n(Cane's n Layne's)/ u]
= 20 / 120
= 1/6
