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3 years ago

0.63 + _____ = $1.00*

Mathematics

2 answers:

svp [43]3 years ago

8 0

0.63+?=1.00
?=1.00-0.63
?=37

Sliva [168]3 years ago

4 0

The answer would be 0.37.

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Evaluate the function f(x) at the given numbers (correct to six decimal places). f(x) = x2 − 3x x2 − 9 , x = 3.1, 3.05, 3.01, 3.

Lostsunrise [7]

Answer:

Values of f(x) for different values of x.

Step-by-step explanation:

We are given the following function in the question:

$f(x) = \displaystyle\frac{x^2-3x}{x^2-9}$

We have to find the value of given function at the following x.

x = 3.1, 3.05, 3.01, 3.001, 3.0001, 2.9, 2.95, 2.99, 2.999, 2.9999

$f(x) = \displaystyle\frac{x^2-3x}{x^2-9}\\\\f(3.1) = \frac{(3.1)^2-3(3.1)}{(3.1)^2-9} = 0.508197\\\\f(3.05) = \frac{(3.05)^2-3(3.05)}{(3.05)^2-9} = 0.504132\\\\f(3.01) = \frac{(3.01)^2-3(3.01)}{(3.01)^2-9} = 0.500832\\\\f(3.001) = \frac{(3.001)^2-3(3.001)}{(3.001)^2-9} = 0.500083\\\\f(3.0001) = \frac{(3.0001)^2-3(3.0001)}{(3.0001)^2-9} = 0.500008\\\\f(2.9) = \frac{(2.9)^2-3(2.9)}{(2.9)^2-9} = 0.4915254\\\\f(2.95) = \frac{(2.95)^2-3(2.95)}{(2.95)^2-9} =0.495798\\\\$

$f(2.99) = \displaystyle\frac{(2.99)^2-3(2.99)}{(2.99)^2-9} =0.499165\\\\f(2.999) = \displaystyle\frac{(2.999)^2-3(2.999)}{(2.999)^2-9} = 0.499917\\\\f(2.9999) = \displaystyle\frac{(2.9999)^2-3(2.9999)}{(2.9999)^2-9} =0.499991$

6 0

3 years ago

I need help on 24 and 25

Furkat [3]

You eat 4_
10 of the coconut

6 0

2 years ago

Which answer is equal to i^45

Stolb23 [73]

Answer:

Step-by-step explanation:

The pattern is as follows

i^1 = i

i^2 = -1

i^3 = -i

i^4 = 1

Following this pattern, i^45 = i.

7 0

3 years ago

Could someone please explain! I cant figure it out.

qwelly [4]

2^-2 = 1/2^2

so: (1/2^2)*(12*3)-5^3

simplify: (1/4)*36-125

36*(1/4) = 36/4 so: 9-125

subtract: -116

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3 years ago

Tan x (degrees) = 31.<br> what is the value of x to the nearest 10th

Inessa05 [86]

88.2 is your answer, have a nice day

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2 years ago