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jonny [76]
3 years ago
14

Which of the following expressions are equivalent to 4 - (-5) +0?

Mathematics
2 answers:
Sedbober [7]3 years ago
8 0

Answer:

A, B, C

Step-by-step explanation:

4 - (-5) + 0

4 - (-5) = 4 + 5 (because a negative + negative = positive)

4 + 5 = 9

a, b and c all equal 9

hopefully this helped you!! :3

Sauron [17]3 years ago
4 0
Answer:a,b,c

ExplainNation:



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Miss Riley's class has 24 students. She has the students in groups. Each group can have no more than 5 students. if every studen
netineya [11]

Answer:

if there can be no more than 5 students, then anything less than 5 students will suffice. However we don’t want any left over ones cause we don’t want that one kid sitting alone during lunch so we can simply put <u><em>4 into each group.</em></u>

Step-by-step explanation:

Hope this helped :DDD

8 0
2 years ago
Read 2 more answers
A segment has endpoint X and Z what are the two names of the segment?
Naily [24]

Segment XZ and segment ZX

8 0
3 years ago
What is the distance to the earth’s horizon from point P?<br><br> Express your answer as a decimal
rewona [7]

Answer:

The distance to the earth's horizon from point P is 216.2198187 mi, appriximately 216.22 mi

Step-by-step explanation:

This is a right triangle:

Hypotenuse: c=3959 mi + 5.9 mi → c=3964.9 mi

Leg 1: a=x=?

Leg 2: b=3959 mi

Using the Pytagorean theorem:

a^2+b^2=c^2

Replacing the known values:

(x)^2+(3959 mi)^2=(3964.9 mi)^2

Solving for x: Squaring:

x^2+15,673,681 mi^2=15,720,432.01 mi^2

Subtracting 15,673,681 mi^2 both sides of the equation:

x^2+15,673,681 mi^2-15,673,681 mi^2=15,720,432.01 mi^2-15,673,681 mi^2

x^2=46,751.01 mi^2

Square root both sides of the equation:

sqrt(x^2)=sqrt(46,751.01 mi^2)

x=216.2198187 mi

x=216.22 mi

3 0
3 years ago
Find the value of y 74 77 89 96
Morgarella [4.7K]
The external angle (53°) is half the difference of the intercepted arcs (y°, 180°), so we have
  53 = (180 - y)/2
  106 = 180 - y
  y = 180 - 106
  y = 74

The appropriate choice for the value of y is ...
  74
4 0
3 years ago
A train leaves boston at 2:00 pm. a second train leaves the same city in the same direction at 6:00 pm. the second train travels
AURORKA [14]
\boxed {\boxed { \text {Distance = Speed x Time}}}

<u>First Train:</u>
Time taken = 9 hours (2pm to 11pm)
Let the speed be x 
Distance = Time x Speed = 9x

<u>Second Train:</u>
Time taken = 5 hours (6pm to 11pm)
Speed = x + 48
Distance = Time x Speed = 5(x + 48)

Since both the distance they traveled are the same, we equate the distance to solve for x.

<u>Solve for x:</u>
9x = 5(x + 48)
9x = 5x + 240
4x = 240
x = 60

<u>Find the speed:</u>
x = 60 mph
x + 48= 108 mph

Answer: The spend of the two trains are 60 mph and 108 mph.
3 0
3 years ago
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