Solve for the following equation for the given variable 24= -2(4t-4)
1 answer:
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Answer:
The surface area of the right regular hexagonal pyramid is 50.78 cm².
Step-by-step explanation:
Given:
A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.
Now, to find the surface area(SA) of the right regular hexagonal pyramid.
So, we find the area of the base(b) first:
Area of the base =
=
On solving we get:
Area of the base(b) =
Then, we find the perimeter(p) :
Perimeter = s × 6
Now, putting the formula for getting the surface area:
Surface area = perimeter × height/2 + Area of the base.
As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>
Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².
Answer:
x = 4 for Lines U and V to be parallel
<u>Skills needed: HS Geo, Angle Theorems, Equations</u>
Step-by-step explanation:
1) We see that there are two angle measures given to us. There is an angle marked with the measure of °, and the other is marked with (
)°.
- First of all, these two angles are categorized alternate interior angles. They are on alternate sides of the transversal, and are within the two lines (not on the outer side of the lines). I will add an image for reference regarding this idea.
- If 2 lines are parallel, alternate interior angles are congruent. This means that:
2) Solving this equation is fairly straightforward.
(add 2 to both sides in order to get the
by itself.
(to get
by itself)
- 132 divided by 33 is 4, and 33x divided by 33 is x, so
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