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san4es73 [151]
3 years ago
11

Express 18/10 to its simplest form​

Mathematics
2 answers:
Usimov [2.4K]3 years ago
8 0

Answer

Simplest Form: 9/5

Step-by-step explanation:

18/10

Greatest Common Factor: 2

18/2 and 10/2 = 9/5

AVprozaik [17]3 years ago
8 0
Common factor is 2

therefore being 9/5 within its simplest form
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Which graph shows the correct solution to the inequality below?
Assoli18 [71]

Answer:

Third Option

Step-by-step explanation:

3x + 18 > 6x - 9

We have to find the value of x for this

Subtract 18 from both sides to leave 3x alone

3x > 6x - 27

Subtract 6x from both sides to be able to find the value of x

-3x > -27

Divide by -3 on both sides

x > 9

The answer would be the third option, since X is anything greater than 9

6 0
3 years ago
Read 2 more answers
Pls help pls pls pls.In a class of 50 students, 3/5 of the students study Maths, 3/10 of the students study English and rest stu
Zina [86]

Answer:

Step-by-step explanation:

No of students study math = 3/5 of 50 = 30

No of students study English = 3/10 of 50 = 15

Total = 30 + 15 = 45

Remaining students = 5

No of students study geography = 5

Fraction of geography to whole class = 5/45 = 9

3 0
3 years ago
For the purpose of purchasing new baseboard and​ carpet, complete parts a and b below.
Phantasy [73]

Answer:

(a)i. Area=72 square feet

ii. Perimeter =34 feet

(b) Baseboard - perimeter

Carpet - area

Step-by-step explanation:

The room is 9ft x 8ft, therefore it is rectangular shaped.

Length=9ft; Breadth=8ft

(a)i. Area of a Rectangle= Length X Breadth

Area of the room=8X9=72 square feet

ii. Perimeter of a Rectangle=2(Length+Breadth)

Perimeter of the room=2(8+9)=2 X 17 =34 feet

(b) A baseboard goes around the edge or boundary of the room, so it has to do with perimeter

A carpet covers the entire floor so it has to do with the area of the room.

3 0
3 years ago
Find (a) arc length and (b) Area of a sector.
barxatty [35]

Answer:

a) 29.45 cm (2 dp)

b) 220.89 cm² (2 dp)

Step-by-step explanation:

<u>Formula</u>

\textsf{Arc length}=r \theta

\textsf{Area of a sector}=\dfrac{1}{2}r^2 \theta

\quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle in radians)}

<u>Calculation</u>

Given:

  • \theta=\dfrac{5 \pi}{8}
  • r = 15 cm

\begin{aligned}\implies \textsf{Arc length} & =r \theta\\& = 15\left(\dfrac{5 \pi}{8}\right)\\& = \dfrac{75}{8} \pi \\& = 29.45\: \sf cm\:(2\:dp)\end{aligned}

\begin{aligned} \implies \textsf{Area of a sector}& =\dfrac{1}{2}r^2 \theta\\\\ & = \dfrac{1}{2}(15^2) \left(\dfrac{5 \pi}{8}\right)\\\\& = \dfrac{225}{2}\left(\dfrac{5 \pi}{8}\right)\\\\ & = \dfrac{1125}{16} \pi \\\\& = 220.89 \: \sf cm^2\:(2\:dp)\end{aligned}

5 0
2 years ago
It was a busy evening at the restaurant. Ron waited on 48 tables for 3 hours. Joe served 45 customers in 5 hours. Sue waited on
Alex Ar [27]

Answer:

Sue

Step-by-step explanation:

34/2= 17 which is the highest out of them all.

7 0
2 years ago
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