Answer:
SAS
Step-by-step explanation:
Given: Two triangles ΔABD and ΔDCA,
We have, AD=AD (common)
∠A=∠A (Given)
BA=CD (Sides opposite to equal angles are always equal)
With the SAS rule of congruency,
ΔABD≅ΔDCA
Answer:
6. x = 3 7. x = 120 8. x= -5
Step-by-step explanation:
the first question is x(-4) + 3 = -9
find the value of x :
-4x + 3 = -9
we can subtract 3 on both sides since we have a value of 3 on the left, which will cancel the value out.
-4x = -12
-4(3) = -12
therefore the answer to problem 6 is x=3
and for 7 :
x / 6 - 9 = 11
we can add 9 on both sides which will cancel it out;
x/6 = 20
120/6 = 20
therefore the answer to the question 7 is 120.
For problem 8 it says :
-3x -5 = 10
we can add 5 on both sides to get:
-3x = 15
-3(-5) = 15
therefore the answer to problem 8 is -5
To convert a decimal into a percent move the decimal point 2 places to the right:
so 0.62 becomes 62%
Answer:
Choice C is the correct answer.
Step-by-step explanation:
Given expression is
(3p-7)(2p²-3p-4)
we have to find the product of linear expression to quardatic expression.
Firstly, multiply 3p to quardatic expression and -7 to quardatic expression and add.
3p(2p²-3p-4)-7(2p²-3p-4)
Multiply 3p to each term of quardatic expression and -7 to each term of quardatic expression and add all terms:
3p(2p²)+3p(-3p)+3p(-4)-7(2p²)-7(-3p)-7(-4)
6p³-9p²-12p-14p²+21p+28
add like terms
6p³+(-9-14)p²+p(-12+21)+28
6p³-23p²+9p+28 which is the correct answer.
The slope intercept form is y = mx + b
you need to find the equation that has a slope of 3/4 and passes through (4,1/3)
Plug in the given into the equation
y = 3/4x + b
to solve for the y-intercept, plug in the given coordinate that the line passes through
1/3 = 3/4(4) + b
1/3 = 3 + b
subtract 3 from both sides
-8/3 = b
now back to the slope intercept equation
y = mx + b
plug in the slope and y-intercept
y = 3/4x - 2 2/3
or
y = 3/4x - 8/3
Hope this helps :)