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ratelena [41]
2 years ago
5

A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have

an average of 77?
72 ,91 ,78, 72
The minimum grade he must get on the last test in order to have an average of 77 is
(Simplify your answer.)
Mathematics
1 answer:
likoan [24]2 years ago
5 0

72 is the minimum grade he must get on the last test in order to have an average of 77.

<u>Step-by-step explanation:</u>

The grades of a student are given 72,91,78,72 and the grade of his last test is not given.

  • You have to find the minimum grade the student shall get, so that the student average must be 77.
  • The four grades are already given. Therefore, we need to find only the fifth grade.

The term average is defined as the sum of all the data in a set divided by the number of data in a set.

Here, the number of data is 5. (Because the students has 4 grades plus one grade for his last test).

The average he should get is 77.

Average = Sum of all grades / number of grades

Let, 'x' be the grade of the last test.

⇒ 77 = (72+91+78+72+x) / 5

⇒ 77 = (313+x) / 5

⇒ 385 = 313 + x

⇒ x = 385 - 313

⇒ x = 72

The minimum grade he must get on the last test is 72.

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Graph of f(x-3) is compressed by a factor of  \frac{1}{8} horizontally of f(x).

<u>Step-by-step explanation:</u>

We have, the graph of f(x)= 2^{x} , on replacing f(x) by f(x-3) we get:

f(x-3)= 2^{x-3} = \frac{2^{x}}{2^{3}} = \frac{1}{8} 2^{x} = \frac{1}{8} f(x).Below shown are the images for graph of f(x) and f(x-3). Both are functions are exponential , and so having exponential graph but f(x-3) is compressed by a factor of  \frac{1}{8} horizontally . Domain and range of both functions are same i.e. F(x) & f(x-3) domain & range are same , just difference in graph : f(x-3) = \frac{1}{8} f(x).

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Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

  • Order of Operations: BPEMDAS
  • Equality Properties

Step-by-step explanation:

<u>Step 1: Define equation</u>

5(x + 4) = -2(-4 - x) + 3

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Distribute:                                   5x + 20 = 8 + 2x + 3
  2. Combine like terms:                   5x + 20 = 2x + 11
  3. Subtract 2x on both sides:        3x + 20 = 11
  4. Subtract 20 on both sides:        3x = -9
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<u>Step 3: Check</u>

<em>Plug in x to verify it's a solution.</em>

  1. Substitute:                    5(-3 + 4) = -2(-4 - -3) + 3
  2. Simplify:                        5(-3 + 4) = -2(-4 + 3) + 3
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  4. Multiply:                        5 = 2 + 3
  5. Add:                              5 = 5

Here we see that 5 does indeed equal 5. ∴ x = -3 is a solution of the equation.

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