1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ratelena [41]
3 years ago
5

A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have

an average of 77?
72 ,91 ,78, 72
The minimum grade he must get on the last test in order to have an average of 77 is
(Simplify your answer.)
Mathematics
1 answer:
likoan [24]3 years ago
5 0

72 is the minimum grade he must get on the last test in order to have an average of 77.

<u>Step-by-step explanation:</u>

The grades of a student are given 72,91,78,72 and the grade of his last test is not given.

  • You have to find the minimum grade the student shall get, so that the student average must be 77.
  • The four grades are already given. Therefore, we need to find only the fifth grade.

The term average is defined as the sum of all the data in a set divided by the number of data in a set.

Here, the number of data is 5. (Because the students has 4 grades plus one grade for his last test).

The average he should get is 77.

Average = Sum of all grades / number of grades

Let, 'x' be the grade of the last test.

⇒ 77 = (72+91+78+72+x) / 5

⇒ 77 = (313+x) / 5

⇒ 385 = 313 + x

⇒ x = 385 - 313

⇒ x = 72

The minimum grade he must get on the last test is 72.

You might be interested in
3 intersecting lines are shown. A line contains points E, D, A, and B. Another line intersects the line at point A and contains
GREYUIT [131]

Answer:

The one with arrows are the answers

->Line segment E B  is bisected by Line segment D F .

->A is the midpoint of Line segment F C .

Line segment F C  bisects Line segment D B.

->Line segment E B  is a segment bisector.

->FA = One-halfFC.

Line segment D A is congruent to Line segment A B .

Step-by-step explanation:

I did it on edge and got it right

5 0
3 years ago
Read 2 more answers
Kathy used 15 ounces of chocolate in her cookies. Cindy used 15% more chocolate in her cookies. How many ounces did Cindy use? (
MaRussiya [10]
Cindy used 17.25 because 15 × .5 = 2.25 and if you add it to 15 ypu get 17.25
5 0
3 years ago
A satellite dish has cross-sections shaped like parabolas. The receiver is located 13 inches from the base along the axis of sym
horsena [70]

Answer:

Depth = 3.3 inches

Step-by-step explanation:

 Given that the shape of the satellite looks like a parabola

The equation of parabola is given as follows

x^2=4\times a\times y

Where

a= 13

Therefore

x^2=4\times 13\times y

x^2=52\times y

Lets take (13 , y) is a

Now by putting the values in the above equation we get

13^2=52\times y

y=\dfrac{13^2}{52}=3.25

y=3.25 in

Therefore the depth of the satellite at the nearest integer will be 3.3 inches.

Depth = 3.3 inches

7 0
3 years ago
Simplify<br><br> PLEASE HELP
SCORPION-xisa [38]

Answer: 3.83

Step-by-step explanation:

(2.24)(1.71)

=3.83

I think you just simply solve it

8 0
3 years ago
Question 10
RSB [31]

Answer:

(x-4)(3x+2)

Step-by-step explanation:

8 0
3 years ago
Other questions:
  • Which expressions are equivalent to 3(-2a-4)+3a
    7·2 answers
  • Simplify the following expression:<br> -8 (5b + 2) -7 ( b-5)
    7·2 answers
  • Plzzzzz helpppppp meeeee
    10·2 answers
  • At a local restaurant, the amount of time that customers have to wait for their food is normally distributed with a mean of 18 m
    8·1 answer
  • What is 0.875 simplest form
    6·2 answers
  • CASLAN UR HERE 56+6x567890-9
    6·2 answers
  • What is the common difference of the following arithmetic sequence?
    11·1 answer
  • Find the missing number
    15·1 answer
  • 83 ÷ 26 = <br> r <br> there should be a remainder
    9·1 answer
  • 9 Calculator What is the median of the data set? 3, 10, 1, 6, 10, 3, 11, 14<br><br><br><br><br>​
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!