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Alla [95]
2 years ago
8

A father is twice as old as his son and the sum of their ages is 75. How old is the father?

Mathematics
1 answer:
castortr0y [4]2 years ago
8 0

Answer: 50

Let's first of all assume the son's age as x.

So,

Father's age will be 2x i.e. twice as old as the son

Given that,

Sum of their ages = 75 years

So,

x + 2x = 75

3x = 75

x = 75/3

x = 25

Hence,

Son's age = x = 25 years

Father's age = 2x = 2 * 25 = 50 years

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The chess club has 50 members. They want to raise $680 for a trip to a competition. The school will give $130 How much must each
Setler79 [48]
So what they need to rais is what the school doesn't give them
so to find that subtract what the school gives them from how much they need
need=680
given=130
680-130=550
they need to raise 550

if each member raises the same amount we fid that by doing
total divided by number of members
total=550
number o fmembers=50
550/50=11
each must raise $11
8 0
3 years ago
While traveling to and from a certain destination, you realized increasing your speed by 40 mph saved 4 hours on your return. If
Luden [163]

Answer:

The speed driven while returning is 88 mph.

Step-by-step explanation:

We are given that while traveling to and from a certain destination, you realized increasing your speed by 40 mph saved 4 hours on your return.

Also, the total distance of the roundtrip was 420 miles.

Let the speed driven while returning be 'x mph' which means that the speed driven while going was '(x - 40) mph' because it has been given that while returning we have increased the speed by 40 mph.

As we know that the Speed-Distance-Time formula is given by;

                         \text {Speed} = \frac{\text{Distance}}{\text{Time}}   or  \text {Time} = \frac{\text{Distance}}{\text{Speed}}

So, according to the question;

\frac{420}{x-40} -\frac{420}{x} = 4 \text{ hours}       where Distance = 420 miles

\frac{420x-420(x-40)}{x(x-40)} = 4

\frac{420x-420x+16800}{x^{2} -40x} = 4

\frac{16800}{x^{2} -40x} = 4

4x^{2} -160x= 16800

4x^{2} -160x- 16800=0

x^{2} -40x- 4200=0

Now finding the roots of the above equation;

Here a = 1, b = -40 and c = -4200

D = b^{2} -4ac

   =  (-40)^{2} -4(1)(-4200) = 18400

Now, the roots of a quadratic equation is given by;

x = \frac{-b\pm \sqrt{D} }{2a}

x = \frac{-(-40)\pm \sqrt{18400} }{2\times 1}

So, the two roots of x are : x = \frac{40-\sqrt{18400} }{2}  and  x = \frac{40+\sqrt{18400} }{2}

Solving these two we get; x = -47.8  and  x = 87.8

Here we ignore the negative value of x, so the speed driven while returning is 87.8 ≈ 88 mph.

8 0
3 years ago
Please help with all of them
Kaylis [27]

Answer:

1 - D

2 - D

3 - B

7 0
3 years ago
Read 2 more answers
Identify the polynomial functions that has zeros at 1,-1 and 2.
frez [133]

Answer:

y=x^{3} -2x^{2} -x+2

Step-by-step explanation:

You are given the roots 1, -1, and 2.

From there, you can combine all these factors into:

(x-1)(x+1)(x-2)

You know this because if you set these factors to 0, it will give you the roots 1, -1, and 2.

You can find the answer by multiplying all the factors and you get:

x^{3} -2x^{2} -x+2

Hope I helped :)

5 0
3 years ago
Questions in the picture
mezya [45]
The answer for the question is 11:45
4 0
2 years ago
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