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3 years ago

7

Find the equation and solve it:

1 answer:

koban [17]3 years ago

8 0

Base and height both measure 6cm.

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Sanford the elf has been asked to choose toys for a child who wants a baby doll, a jigsaw puzzle, and a stuffed dog. He looks on

zmey [24]

Answer: There are 198 different combinations.

Step-by-step explanation:

To solve this type of problem, first, we need to identify the selections.

We have 3 selections.

Baby doll, Jigsaw puzzle, and a stuffed dog.

Now, we need to count the numbers of options for each case:

Baby doll: 11 options.

Jigsaw Puzzle: 6 options.

Stuffed dog: 3 options.

To find the total number of different combinations, we need to multiply all the numbers of options together, this is:

Combinations = 11*6*3 = 198

There are 198 different combinations.

5 0

3 years ago

Brainliest question please help please help me now plz

Kruka [31]

Answer:

Option A) Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

$d\sqrt{(y2-y1)^2+(x2-x1)^2 }$

we have

A(-5,-8),M(-1,-3)

substitute the values

$r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}$

$r=\sqrt{(5)^{2}+(4)^{2}}$

$r=\sqrt{41}\ units$

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

$d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}$

$d=\sqrt{(2)^{2}+(-6)^{2}}$

$d=\sqrt{40}\ units$

so

$\sqrt{40}\ units< \sqrt{41}\ units$

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

Hope that helped :)

8 0

3 years ago

Nicolas sold 86 newspapers on Monday 79 on Tuesday and 68 on Wednesday and 83 on Friday how many newspapers did Nicholas sell on

natima [27]

Answer:

75

Step-by-step explanation:

86+79+68+83=316

391-316=75

8 0

3 years ago

Read 2 more answers

4 x 5 - (2² - 2) =? <br> (18 ÷ 3) + (3² - 7) =?

OverLord2011 [107]

4x5-(2 (2) - 2 ) = 14
(18/ 3) + (3 (2) - 7) 8

7 0

3 years ago

Why are handcuffs like souvenirs?

ArbitrLikvidat [17]

<u>Part A)</u> $7(a+b)=7a+$

Using the distributive property

$7(a+b)=7a+7b$

therefore

<u>the answer Part A is</u>

$9-----> A$

<u>Part R)</u> $4(5+x)=20+$

Using the distributive property

$4(5+x)=20+4x$

therefore

<u>the answer Part R is</u>

$14-----> R$

<u>Part Y)</u> $3(2x+9)=6x+$

Using the distributive property

$3(2x+9)=6x+27$

therefore

<u>the answer Part Y is</u>

$4-----> Y$

Part S) $8(3x+1)=+8$

Using the distributive property

$8(3x+1)=24x+8$

therefore

<u>the answer Part S is</u>

$23-----> S$

<u>Part O)</u> $a(4+b)=+ab$

Using the distributive property

$a(4+b)=4a+ab$

therefore

<u>the answer Part O is</u>

$17-----> O$

<u>Part E)</u> $x(y+10)=+10x$

Using the distributive property

$x(y+10)=xy+10x$

therefore

<u>the answer Part E is</u>

$3-----> E$

<u>Part I)</u> $2(7x+4y)=14x+$

Using the distributive property

$2(7x+4y)=14x+8y$

therefore

<u>the answer Part I is</u>

$20-----> I$

<u>Part D)</u> $6(9+5x)=54+$

Using the distributive property

$6(9+5x)=54+30x$

therefore

<u>the answer Part D is</u>

$10-----> D$

<u>Part W)</u> $x(a+3b)=+3bx$

Using the distributive property

$x(a+3b)=ax+3bx$

therefore

<u>the answer Part W is</u>

$18-----> W$

<u>Part E)</u> $a(8x+2y)=8ax+$

Using the distributive property

$a(8x+2y)=8ax+2ay$

therefore

<u>the answer Part E is</u>

$7-----> E$

<u>Part T)</u> $0.5(4a+10)=2a+$

Using the distributive property

<u>Part T)</u> $0.5(4a+10)=2a+5$

therefore

<u>the answer Part T is</u>

$1-----> T$

<u>Part R)</u> $(2/3)(12+9y)=8+$

Using the distributive property

$(2/3)(12+9y)=8+6y$

therefore

<u>the answer Part R is</u>

$6-----> R$

<u>Part O)</u> $5x+5y=5(x+\ )$

$5x+5y=5(x+y)$

therefore

<u>the answer Part O is</u>

$13-----> O$

<u>Part T)</u> $9a+9b=9(\ +b)$

$9a+9b=9(a+b)$

therefore

<u>the answer Part T is</u>

$22-----> T$

Part W) $4m+4n=\ (m+n)$

$4m+4n=4(m+n)$

therefore

<u>the answer Part W is</u>

$16-----> W$

<u>Part H)</u> $ab+3a=a(b+\ )$

$ab+3a=a(b+3)$

therefore

<u>the answer Part H is</u>

$2-----> H$

<u>Part E)</u> $xy+15x=\ (y+15)$

$xy+15x=x(y+15)$

therefore

<u>the answer Part E is</u>

$11-----> E$

Part A) $bu+uv=\ (b+v)$

$bu+uv=u(b+v)$

therefore

<u>the answer Part A is</u>

$5-----> A$

<u>Part F)</u> $(2/5)m+(2/5)n=(2/5)( \ +n)$

$(2/5)m+(2/5)n=(2/5)(m+n)$

therefore

<u>the answer Part F is</u>

$12-----> F$

<u>Part M)</u> $(3/4)a+(3/4)b+(3/4)c=\ (a+b+c)$

$(3/4)a+(3/4)b+(3/4)c=(3/4)(a+b+c)$

therefore

<u>the answer Part M is</u>

$8-----> M$

<u>Part S)</u> $7ax+2ay=a(7x+\ )$

$7ax+2ay=a(7x+2y)$

therefore

<u>the answer Part S is</u>

$21-----> S$

Part T) $4kx+11ky=\ (4x+11y)$

$4kx+11ky=k(4x+11y)$

therefore

<u>the answer Part T is</u>

$15-----> T$

<u>Part R)</u> $3ay+8by=y(\ +8b)$

$3ay+8by=y(3a+8b)$

therefore

<u>the answer Part R is</u>

$19-----> R$

<u>the answer is</u>

they are made for two wrists

4 0

4 years ago

Read 2 more answers