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2 years ago

A store has a sale for 15% off. You want a jacket that was originally $45. How much

Mathematics

1 answer:

Travka [436]2 years ago

4 0

Answer:

es 51.75

Step-by-step explanation:

por que al sumar 45 + 15 porciento da 51.75

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Suppose an airline accepted 12 reservations for a commuter plane with 10seats. They know that 7 reservations went to regular com

kvv77 [185]

Answer:

<h2>See the explanation.</h2>

Step-by-step explanation:

(a)

7 persons will show up for sure, hence there is not any kind of probability here.

The other 5 persons have 50% chance to show up.

The flight will be overbooked, if either 4 will come or 5 will come.

From the total 5 persons, 4 can be chosen in $^5C_4 = 5$ ways.

The probability that any four among the 5 will come is $5\times(\frac{50}{100} )^{5} = 5\times(\frac{1}{2} )^{5} = \frac{5}{32}$ .

The probability that all of the 5 passengers will come is $\frac{1}{32}$ .

Hence, the required probability is $\frac{5}{32} + \frac{1}{32} = \frac{6}{32} = \frac{3}{16}$ .

(b)

The probability that there will be exactly 10 passengers on the flight is $^5C_3\times (\frac{1}{2} )^5 = \frac{20}{2} \times\frac{1}{32} = \frac{10}{32} = \frac{5}{16}$ .

The probability that there will be no empty seats in the plane is $\frac{3}{16} + \frac{5}{16} = \frac{1}{2}$ .

Hence, probability of having empty seats is $1 - \frac{1}{2} = \frac{1}{2}$ .

6 0

3 years ago

A product is made up of components A, B, C, D, E, F, G, H, I, and J. Components A, B, C, and F have a 1/10,000 chance of failure

lesantik [10]

Answer:

The overall reliability is 99.7402 %

Step-by-step explanation:

The overall reliability of the product is calculated as the product of the working probability of the components.

For components A,B,C and F we have :

$P(failure)=\frac{1}{10000}$

⇒

$P(Work)=1-\frac{1}{10000}=\frac{9999}{10000}=0.9999$

For components D,E,G and H we have :

$P(failure)=\frac{3}{10000}$

⇒

$P(Work)=1-\frac{3}{10000}=\frac{9997}{10000}=0.9997$

Finally, for components I and J :

$P(failure)=\frac{5}{10000}$

⇒

$P(Work)=1-\frac{5}{10000}=\frac{9995}{10000}=0.9995$

Now we multiply all the working probabilities. We mustn't forget that we have got ten components in this case :

Components A,B,C and F with a working probability of 0.9999

Components D,E,G and H with a working probability of 0.9997

Components I and J with a working probability of 0.9995

Overall reliability = $(0.9999)^{4}(0.9997)^{4}(0.9995)^{2}=0.997402$

0.997402 = 99.7402 %

4 0

3 years ago

800 students are going on a school trip by bus.

Tema [17]

The answer is twenty four

6 0

3 years ago

Read 2 more answers

Answer each question. What is 35% of 90x? What percent of 16x is 9x?

Ket [755]

Answer:

35% of 90x = 31.5

16x is 9x =

Step-by-step explanation:

35 /100 x 90 = 31.5

6 0

3 years ago

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How to write 30000+300+3 in standard form

Elis [28]

Answer:

30303

Step-by-step explanation:

math bro

7 0

3 years ago