(5x-2y)(3x-2y)
Dont give me anything give it to the other lad down there
As AB and ED are parallel, they have the same slope. This means that since lines that are colllinear with parallel segments are parallel, lines l and m are parallel.
The first step is to find the slope. Use the slope formula
m = (y2-y1)/(x2-x1)
The two points are (x1,y1) = (-1,5) and (x2,y2) = (2,-1)
So,
x1 = -1
y1 = 5
and
x2 = 2
y2 = -1
will be plugged into the slope formula to get...
m = (y2-y1)/(x2-x1)
m = (-1-5)/(2-(-1))
m = (-1-5)/(2+1)
m = (-6)/(3)
m = -2
The slope is -2
Use m = -2 and one of the points to find the y intercept b. I'll use the point (x,y) = (-1,5) ---> x = -1, y = 5
y = mx+b ... slope intercept form
5 = -2*(-1)+b
5 = 2+b
5-2 = 2+b-2
3 = b
b = 3
The y intercept is 3
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m = -2 is the slope
b = 3 is the y intercept
Therefore y = mx+b turns into y = -2x+3 as the equation that goes through the two points
